let n, k be Element of NAT ; not PFCrt n,k in PFBrt (n + 1),k
assume
PFCrt n,k in PFBrt (n + 1),k
; contradiction
then
( ex m being non empty Element of NAT st
( m <= n + 1 & PFCrt n,k = PFArt m,k ) or PFCrt n,k = PFCrt (n + 1),k )
by Def4;
hence
contradiction
by Th20, Th21; verum