let f be Function; ( f is one-to-one implies for x, y being set holds
( [y,x] in f " iff [x,y] in f ) )
assume A1:
f is one-to-one
; for x, y being set holds
( [y,x] in f " iff [x,y] in f )
let x, y be set ; ( [y,x] in f " iff [x,y] in f )
dom (f " ) = rng f
by A1, FUNCT_1:55;
then
( y in dom (f " ) & x = (f " ) . y iff ( x in dom f & y = f . x ) )
by A1, FUNCT_1:54;
hence
( [y,x] in f " iff [x,y] in f )
by FUNCT_1:8; verum