let G be _Graph; for W being Walk of G
for m, n being odd Element of NAT st m <= n & n <= len W & W . m = W . n holds
len (W .remove m,n) = ((len W) + m) - n
let W be Walk of G; for m, n being odd Element of NAT st m <= n & n <= len W & W . m = W . n holds
len (W .remove m,n) = ((len W) + m) - n
let m, n be odd Element of NAT ; ( m <= n & n <= len W & W . m = W . n implies len (W .remove m,n) = ((len W) + m) - n )
assume that
A1:
m <= n
and
A2:
n <= len W
and
A3:
W . m = W . n
; len (W .remove m,n) = ((len W) + m) - n
(len (W .remove m,n)) + n = (len W) + m
by A1, A2, A3, Lm24;
hence
len (W .remove m,n) = ((len W) + m) - n
; verum