for x being real number st x in dom sec holds
( x + (2 * PI ) in dom sec & x - (2 * PI ) in dom sec & sec . x = sec . (x + (2 * PI )) )
proof
let x be
real number ;
( x in dom sec implies ( x + (2 * PI ) in dom sec & x - (2 * PI ) in dom sec & sec . x = sec . (x + (2 * PI )) ) )
assume A1:
x in dom sec
;
( x + (2 * PI ) in dom sec & x - (2 * PI ) in dom sec & sec . x = sec . (x + (2 * PI )) )
then
x in (dom cos ) \ (cos " {0 })
by RFUNCT_1:def 8;
then
(
x in dom cos & not
x in cos " {0 } )
by XBOOLE_0:def 5;
then A2:
not
cos . x in {0 }
by FUNCT_1:def 13;
then
cos . x <> 0
by TARSKI:def 1;
then
cos . (x + (2 * PI )) <> 0
by SIN_COS:83;
then
not
cos . (x + (2 * PI )) in {0 }
by TARSKI:def 1;
then
(
x + (2 * PI ) in dom cos & not
x + (2 * PI ) in cos " {0 } )
by FUNCT_1:def 13, SIN_COS:27;
then A3:
x + (2 * PI ) in (dom cos ) \ (cos " {0 })
by XBOOLE_0:def 5;
cos . (x - (2 * PI )) = cos . ((x - (2 * PI )) + (2 * PI ))
by L2, Th1, SIN_COS:27;
then
(
x - (2 * PI ) in dom cos & not
x - (2 * PI ) in cos " {0 } )
by A2, FUNCT_1:def 13, SIN_COS:27;
then A4:
x - (2 * PI ) in (dom cos ) \ (cos " {0 })
by XBOOLE_0:def 5;
then A5:
(
x + (2 * PI ) in dom sec &
x - (2 * PI ) in dom sec )
by A3, RFUNCT_1:def 8;
sec . (x + (2 * PI )) =
(cos . (x + (2 * PI ))) "
by A5, RFUNCT_1:def 8
.=
(cos . x) "
by SIN_COS:83
.=
sec . x
by A1, RFUNCT_1:def 8
;
hence
(
x + (2 * PI ) in dom sec &
x - (2 * PI ) in dom sec &
sec . x = sec . (x + (2 * PI )) )
by A3, A4, RFUNCT_1:def 8;
verum
end;
hence
sec is 2 * PI -periodic
by Th1; verum