let x0 be Real; for f being PartFunc of REAL ,REAL st f is_differentiable_in x0 holds
ex R being REST st
( R . 0 = 0 & R is_continuous_in 0 )
let f be PartFunc of REAL ,REAL ; ( f is_differentiable_in x0 implies ex R being REST st
( R . 0 = 0 & R is_continuous_in 0 ) )
assume
f is_differentiable_in x0
; ex R being REST st
( R . 0 = 0 & R is_continuous_in 0 )
then consider N being Neighbourhood of x0 such that
N c= dom f
and
A1:
ex L being LINEAR ex R being REST st
for x being Real st x in N holds
(f . x) - (f . x0) = (L . (x - x0)) + (R . (x - x0))
by Def5;
consider L being LINEAR, R being REST such that
A2:
for x being Real st x in N holds
(f . x) - (f . x0) = (L . (x - x0)) + (R . (x - x0))
by A1;
take
R
; ( R . 0 = 0 & R is_continuous_in 0 )
consider p being Real such that
A3:
for r being Real holds L . r = p * r
by Def4;
(f . x0) - (f . x0) = (L . (x0 - x0)) + (R . (x0 - x0))
by A2, RCOMP_1:37;
then A4:
0 = (p * 0 ) + (R . 0 )
by A3;
hence
R . 0 = 0
; R is_continuous_in 0
A5:
now set s3 =
cs;
let h be
convergent_to_0 Real_Sequence;
( R /* h is convergent & lim (R /* h) = R . 0 )A6:
cs . 1
= 0
by FUNCOP_1:13;
(h " ) (#) (R /* h) is
convergent
by Def3;
then
(h " ) (#) (R /* h) is
bounded
by SEQ_2:27;
then consider M being
real number such that
M > 0
and A7:
for
n being
Element of
NAT holds
abs (((h " ) (#) (R /* h)) . n) < M
by SEQ_2:15;
A8:
h is
convergent
by Def1;
then A9:
abs h is
convergent
by SEQ_4:26;
A10:
h is
non-zero
by Def1;
lim h = 0
by Def1;
then lim (abs h) =
abs 0
by A8, SEQ_4:27
.=
0
by ABSVALUE:7
;
then A14:
lim (M (#) (abs h)) =
M * 0
by A9, SEQ_2:22
.=
lim cs
by A6, SEQ_4:40
;
A15:
M (#) (abs h) is
convergent
by A9, SEQ_2:21;
then A16:
abs (R /* h) is
convergent
by A14, A11, SEQ_2:33;
lim cs = 0
by A6, SEQ_4:40;
then
lim (abs (R /* h)) = 0
by A15, A14, A11, SEQ_2:34;
hence
(
R /* h is
convergent &
lim (R /* h) = R . 0 )
by A4, A16, SEQ_4:28;
verum end;
hence
R is_continuous_in 0
by FCONT_1:2; verum