let n be Nat; for i1, i2 being Nat st 1 <= i1 & i1 <= n & Base_FinSeq n,i1 = Base_FinSeq n,i2 holds
i1 = i2
let i1, i2 be Nat; ( 1 <= i1 & i1 <= n & Base_FinSeq n,i1 = Base_FinSeq n,i2 implies i1 = i2 )
assume that
A1:
1 <= i1
and
A2:
i1 <= n
and
A3:
Base_FinSeq n,i1 = Base_FinSeq n,i2
; i1 = i2
(Base_FinSeq n,i1) . i1 = 1
by A1, A2, MATRIXR2:75;
hence
i1 = i2
by A1, A2, A3, MATRIXR2:76; verum