let R be finite RelStr ; for C being Coloring of R holds card C >= clique# R
let C be Coloring of R; card C >= clique# R
assume A:
card C < clique# R
; contradiction
consider A being Clique of R such that
B:
card A = clique# R
by Lheight;
( card (card C) = card C & card (card A) = card A )
;
then C:
card C in card A
by A, B, NAT_1:42;
set cR = the carrier of R;
per cases
( R is empty or not R is empty )
;
suppose S1:
R is
empty
;
contradictionthus
contradiction
by A, S1;
verum end; suppose S1:
not
R is
empty
;
contradictiondefpred S1[
set ,
set ]
means ( $1
in A & $2
in C & $1
in $2 );
P:
for
x being
set st
x in A holds
ex
y being
set st
(
y in C &
S1[
x,
y] )
consider f being
Function of
A,
C such that Q:
for
x being
set st
x in A holds
S1[
x,
f . x]
from FUNCT_2:sch 1(P);
consider x,
y being
set such that A1:
x in A
and B1:
y in A
and C1:
x <> y
and D1:
f . x = f . y
by S1, C, FINSEQ_4:80;
f . x in C
by A1, FUNCT_2:7;
then E1:
f . x is
StableSet of
R
by LACpart;
(
x in f . x &
y in f . x )
by D1, A1, B1, Q;
hence
contradiction
by E1, A1, B1, C1, ACClique;
verum end; end;