let x, h be Real; for f being Function of REAL ,REAL st ( for x being Real holds f . x = 1 / (sin x) ) & sin x <> 0 & sin (x + h) <> 0 holds
(fD f,h) . x = - ((2 * ((sin x) - (sin (x + h)))) / ((cos ((2 * x) + h)) - (cos h)))
let f be Function of REAL ,REAL ; ( ( for x being Real holds f . x = 1 / (sin x) ) & sin x <> 0 & sin (x + h) <> 0 implies (fD f,h) . x = - ((2 * ((sin x) - (sin (x + h)))) / ((cos ((2 * x) + h)) - (cos h))) )
assume that
A1:
for x being Real holds f . x = 1 / (sin x)
and
A2:
( sin x <> 0 & sin (x + h) <> 0 )
; (fD f,h) . x = - ((2 * ((sin x) - (sin (x + h)))) / ((cos ((2 * x) + h)) - (cos h)))
A3:
f . (x + h) = 1 / (sin (x + h))
by A1;
(fD f,h) . x =
(1 / (sin (x + h))) - (f . x)
by A3, DIFF_1:3
.=
(1 / (sin (x + h))) - (1 / (sin x))
by A1
.=
((1 * (sin x)) - (1 * (sin (x + h)))) / ((sin (x + h)) * (sin x))
by A2, XCMPLX_1:131
.=
((sin x) - (sin (x + h))) / (- ((1 / 2) * ((cos ((x + h) + x)) - (cos ((x + h) - x)))))
by SIN_COS4:33
.=
((sin x) - (sin (x + h))) / ((- (1 / 2)) * ((cos ((x + h) + x)) - (cos ((x + h) - x))))
.=
(((sin x) - (sin (x + h))) / (- (1 / 2))) / ((cos ((2 * x) + h)) - (cos h))
by XCMPLX_1:79
.=
(- 2) * (((sin x) - (sin (x + h))) / ((cos ((2 * x) + h)) - (cos h)))
;
hence
(fD f,h) . x = - ((2 * ((sin x) - (sin (x + h)))) / ((cos ((2 * x) + h)) - (cos h)))
; verum