let Fy be finite-yielding Function; for X being finite set st dom Fy = X holds
for P being Function of (card X),X st P is one-to-one holds
ex XFS being XFinSequence of NAT st
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS )
let X be finite set ; ( dom Fy = X implies for P being Function of (card X),X st P is one-to-one holds
ex XFS being XFinSequence of NAT st
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS ) )
assume A1:
dom Fy = X
; for P being Function of (card X),X st P is one-to-one holds
ex XFS being XFinSequence of NAT st
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS )
let P be Function of (card X),X; ( P is one-to-one implies ex XFS being XFinSequence of NAT st
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS ) )
assume A2:
P is one-to-one
; ex XFS being XFinSequence of NAT st
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS )
per cases
( X = {} or X <> {} )
;
suppose
X <> {}
;
ex XFS being XFinSequence of NAT st
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS )then reconsider cX =
card X as non
empty set ;
deffunc H1(
Element of
cX)
-> Element of
NAT =
card ((Fy * P) . $1);
consider XFS being
Function of
cX,
NAT such that A4:
for
x being
Element of
cX holds
XFS . x = H1(
x)
from FUNCT_2:sch 4();
A5:
dom XFS = cX
by FUNCT_2:def 1;
then reconsider XFS =
XFS as
XFinSequence by AFINSQ_1:7;
reconsider XFS =
XFS as
XFinSequence of
NAT ;
take
XFS
;
( dom XFS = card X & ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS )thus
card X = dom XFS
by FUNCT_2:def 1;
( ( for z being set st z in dom XFS holds
XFS . z = card ((Fy * P) . z) ) & Card_Intersection Fy,1 = Sum XFS )thus
for
z being
set st
z in dom XFS holds
XFS . z = card ((Fy * P) . z)
by A4, A5;
Card_Intersection Fy,1 = Sum XFSthus
Card_Intersection Fy,1
= Sum XFS
verumproof
deffunc H2(
set )
-> set =
((P . $1) .--> 0 ) +* ((X \ {(P . $1)}) --> 1);
A6:
for
x being
set st
x in cX holds
H2(
x)
in Choose X,1,
0 ,1
proof
let x be
set ;
( x in cX implies H2(x) in Choose X,1,0 ,1 )
assume
x in cX
;
H2(x) in Choose X,1,0 ,1
then
x in dom P
by CARD_1:47, FUNCT_2:def 1;
then
P . x in rng P
by FUNCT_1:def 5;
then A7:
{(P . x)} \/ (X \ {(P . x)}) = X
by ZFMISC_1:140;
(
{(P . x)} misses X \ {(P . x)} &
card {(P . x)} = 1 )
by CARD_1:50, XBOOLE_1:79;
hence
H2(
x)
in Choose X,1,
0 ,1
by A7, Th20;
verum
end;
consider P1 being
Function of
cX,
(Choose X,1,0 ,1) such that A8:
for
z being
set st
z in cX holds
P1 . z = H2(
z)
from FUNCT_2:sch 2(A6);
Choose X,1,
0 ,1
c= rng P1
proof
card X = card (card X)
;
then A9:
P is
onto
by A2, STIRL2_1:70;
let z be
set ;
TARSKI:def 3 ( not z in Choose X,1,0 ,1 or z in rng P1 )
assume
z in Choose X,1,
0 ,1
;
z in rng P1
then consider F being
Function of
X,
{0 ,1} such that A10:
F = z
and A11:
card (F " {0 }) = 1
by Def1;
consider x1 being
set such that A12:
F " {0 } = {x1}
by A11, CARD_2:60;
A13:
x1 in {x1}
by TARSKI:def 1;
then
x1 in X
by A12;
then
x1 in rng P
by A9, FUNCT_2:def 3;
then consider x2 being
set such that A14:
x2 in dom P
and A15:
P . x2 = x1
by FUNCT_1:def 5;
A16:
P1 . x2 = F
proof
set F1 =
(X \ {(P . x2)}) --> 1;
set F0 =
(P . x2) .--> 0 ;
set P1x =
((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1);
A17:
{(P . x2)} \/ (X \ {(P . x2)}) = X
by A12, A13, A15, ZFMISC_1:140;
A18:
now let d be
set ;
( d in dom F implies (((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = F . d )assume A19:
d in dom F
;
(((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = F . dnow per cases
( d in {(P . x2)} or d in X \ {(P . x2)} )
by A17, A19, XBOOLE_0:def 3;
suppose A23:
d in X \ {(P . x2)}
;
(((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = F . dthen
d in dom ((X \ {(P . x2)}) --> 1)
by FUNCT_2:def 1;
then
(((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = ((X \ {(P . x2)}) --> 1) . d
by FUNCT_4:14;
then A24:
(((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = 1
by A23, FUNCOP_1:13;
A25:
X = dom F
by FUNCT_2:def 1;
not
d in {x1}
by A15, A23, XBOOLE_0:def 5;
then
not
F . d in {0 }
by A12, A23, A25, FUNCT_1:def 13;
then A26:
not
F . d = 0
by TARSKI:def 1;
F . d in rng F
by A23, A25, FUNCT_1:def 5;
hence
(((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = F . d
by A24, A26, TARSKI:def 2;
verum end; end; end; hence
(((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) . d = F . d
;
verum end;
dom ((P . x2) .--> 0 ) = {(P . x2)}
by FUNCOP_1:19;
then A27:
X = (dom ((P . x2) .--> 0 )) \/ (dom ((X \ {(P . x2)}) --> 1))
by A17, FUNCT_2:def 1;
(
dom F = X &
dom (((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1)) = (dom ((P . x2) .--> 0 )) \/ (dom ((X \ {(P . x2)}) --> 1)) )
by FUNCT_2:def 1, FUNCT_4:def 1;
then
((P . x2) .--> 0 ) +* ((X \ {(P . x2)}) --> 1) = F
by A27, A18, FUNCT_1:9;
hence
P1 . x2 = F
by A8, A14;
verum
end;
card (Choose X,1,0 ,1) = (card X) choose 1
by Th18;
then
card (Choose X,1,0 ,1) = cX
by NAT_1:14, NEWTON:33;
then
dom P1 = cX
by CARD_1:47, FUNCT_2:def 1;
hence
z in rng P1
by A10, A14, A16, FUNCT_1:def 5;
verum
end;
then A28:
Choose X,1,
0 ,1
= rng P1
by XBOOLE_0:def 10;
then A29:
P1 is
onto
by FUNCT_2:def 3;
card (Choose X,1,0 ,1) = (card X) choose 1
by Th18;
then A30:
card X = card (Choose X,1,0 ,1)
by A28, NAT_1:14, NEWTON:33;
then reconsider P1 =
P1 as
Function of
(card (Choose X,1,0 ,1)),
(Choose X,1,0 ,1) ;
card (card X) = card X
;
then
P1 is
one-to-one
by A29, A30, STIRL2_1:70;
then consider XFS1 being
XFinSequence of
NAT such that A31:
dom XFS1 = dom P1
and A32:
for
z being
set for
f being
Function st
z in dom XFS1 &
f = P1 . z holds
XFS1 . z = card (Intersection Fy,f,0 )
and A33:
Card_Intersection Fy,1
= Sum XFS1
by A1, Def4;
(
Choose X,1,
0 ,1
= {} implies
card (Choose X,1,0 ,1) = {} )
;
then A34:
dom P1 = card (Choose X,1,0 ,1)
by FUNCT_2:def 1;
A35:
for
z being
set st
z in dom XFS1 holds
XFS1 . z = XFS . z
proof
let z be
set ;
( z in dom XFS1 implies XFS1 . z = XFS . z )
assume A36:
z in dom XFS1
;
XFS1 . z = XFS . z
H2(
z)
in Choose X,1,
0 ,1
by A6, A30, A31, A36;
then consider f being
Function of
X,
{0 ,1} such that A37:
f = H2(
z)
and A38:
card (f " {0 }) = 1
by Def1;
consider x1 being
set such that A39:
f " {0 } = {x1}
by A38, CARD_2:60;
P1 . z = H2(
z)
by A8, A30, A31, A36;
then A40:
XFS1 . z = card (Intersection Fy,f,0 )
by A32, A36, A37;
A41:
0 in {0 }
by TARSKI:def 1;
A42:
dom ((X \ {(P . z)}) --> 1) = X \ {(P . z)}
by FUNCOP_1:19;
A43:
P . z in {(P . z)}
by TARSKI:def 1;
{(P . z)} = dom ((P . z) .--> 0 )
by FUNCOP_1:19;
then A44:
P . z in (dom ((P . z) .--> 0 )) \/ (dom ((X \ {(P . z)}) --> 1))
by A43, XBOOLE_0:def 3;
( not
P . z in X \ {(P . z)} &
((P . z) .--> 0 ) . (P . z) = 0 )
by A43, FUNCOP_1:13, XBOOLE_0:def 5;
then A45:
H2(
z)
. (P . z) = 0
by A44, A42, FUNCT_4:def 1;
P . z in dom H2(
z)
by A44, FUNCT_4:def 1;
then A46:
P . z in f " {0 }
by A37, A45, A41, FUNCT_1:def 13;
then
P . z = x1
by A39, TARSKI:def 1;
then A47:
card (Intersection Fy,f,0 ) = card (Fy . (P . z))
by A39, Th37;
A48:
XFS . z = card ((Fy * P) . z)
by A4, A30, A31, A36;
z in dom P
by A30, A31, A34, A36, A46, FUNCT_2:def 1;
hence
XFS1 . z = XFS . z
by A47, A40, A48, FUNCT_1:23;
verum
end;
dom XFS1 = dom XFS
by A30, A31, A34, FUNCT_2:def 1;
hence
Card_Intersection Fy,1
= Sum XFS
by A33, A35, FUNCT_1:def 17;
verum
end; end; end;