let z1 be Tuple of 1, BOOLEAN ; :: thesis: ( z1 = <*FALSE *> implies Absval z1 = 0 )
A1: ex k being Element of NAT st Binary z1 = <*k*> by FINSEQ_2:117;
assume z1 = <*FALSE *> ; :: thesis: Absval z1 = 0
then A2: z1 /. 1 = FALSE by FINSEQ_4:25;
1 in Seg 1 ;
then (Binary z1) /. 1 = IFEQ (z1 /. 1),FALSE ,0 ,(2 to_power (1 -' 1)) by Def6
.= 0 by A2, FUNCOP_1:def 8 ;
hence Absval z1 = addnat $$ <*0 *> by A1, FINSEQ_4:25
.= 0 by FINSOP_1:12 ;
:: thesis: verum