let n be non empty Nat; for i being Integer
for j being Nat st 1 <= j & j <= n holds
(2sComplement (n + 1),i) /. j = (2sComplement n,i) /. j
let i be Integer; for j being Nat st 1 <= j & j <= n holds
(2sComplement (n + 1),i) /. j = (2sComplement n,i) /. j
let j be Nat; ( 1 <= j & j <= n implies (2sComplement (n + 1),i) /. j = (2sComplement n,i) /. j )
assume that
A1:
1 <= j
and
A2:
j <= n
; (2sComplement (n + 1),i) /. j = (2sComplement n,i) /. j
A3:
j in Seg n
by A1, A2, FINSEQ_1:3;
n <= n + 1
by NAT_1:11;
then
j <= n + 1
by A2, XXREAL_0:2;
then A4:
j in Seg (n + 1)
by A1, FINSEQ_1:3;
set N = abs ((2 to_power (MajP n,(abs i))) + i);
set M = abs ((2 to_power (MajP (n + 1),(abs i))) + i);
A5:
( i < 0 implies ((abs ((2 to_power (MajP (n + 1),(abs i))) + i)) div (2 to_power (j -' 1))) mod 2 = ((abs ((2 to_power (MajP n,(abs i))) + i)) div (2 to_power (j -' 1))) mod 2 )
proof
MajP (n + 1),
(abs i) >= MajP n,
(abs i)
by Th22, NAT_1:11;
then consider m being
Nat such that A6:
MajP (n + 1),
(abs i) = (MajP n,(abs i)) + m
by NAT_1:10;
reconsider m =
m as
Nat ;
set P =
MajP n,
(abs i);
assume A7:
i < 0
;
((abs ((2 to_power (MajP (n + 1),(abs i))) + i)) div (2 to_power (j -' 1))) mod 2 = ((abs ((2 to_power (MajP n,(abs i))) + i)) div (2 to_power (j -' 1))) mod 2
set Q = 2
to_power (MajP n,(abs i));
A8:
((2 to_power (MajP n,(abs i))) * (2 to_power m)) mod (2 to_power (MajP n,(abs i))) = 0
by NAT_D:13;
2
to_power (MajP (n + 1),(abs i)) >= abs i
by Def1;
then
2
to_power (MajP (n + 1),(abs i)) >= - i
by A7, ABSVALUE:def 1;
then
(2 to_power (MajP (n + 1),(abs i))) + i >= (- i) + i
by XREAL_1:8;
then abs ((2 to_power (MajP (n + 1),(abs i))) + i) =
(2 to_power ((MajP n,(abs i)) + m)) + i
by A6, ABSVALUE:def 1
.=
((2 to_power (MajP n,(abs i))) * (2 to_power m)) + i
by POWER:32
;
then A9:
(abs ((2 to_power (MajP (n + 1),(abs i))) + i)) mod (2 to_power (MajP n,(abs i))) =
((((2 to_power (MajP n,(abs i))) * (2 to_power m)) mod (2 to_power (MajP n,(abs i)))) + (i mod (2 to_power (MajP n,(abs i))))) mod (2 to_power (MajP n,(abs i)))
by INT_3:14
.=
(i mod (2 to_power (MajP n,(abs i)))) mod (2 to_power (MajP n,(abs i)))
by A8
;
A10:
(2 to_power (MajP n,(abs i))) mod (2 to_power (MajP n,(abs i))) = 0
by NAT_D:25;
j + (- 1) >= 1
+ (- 1)
by A1, XREAL_1:8;
then
j -' 1
= j - 1
by XREAL_0:def 2;
then A11:
j -' 1
< n
by A2, XREAL_1:148, XXREAL_0:2;
MajP n,
(abs i) >= n
by Def1;
then A12:
j -' 1
< MajP n,
(abs i)
by A11, XXREAL_0:2;
2
to_power (MajP n,(abs i)) >= abs i
by Def1;
then
2
to_power (MajP n,(abs i)) >= - i
by A7, ABSVALUE:def 1;
then
(2 to_power (MajP n,(abs i))) + i >= (- i) + i
by XREAL_1:8;
then
abs ((2 to_power (MajP n,(abs i))) + i) = (2 to_power (MajP n,(abs i))) + i
by ABSVALUE:def 1;
then (abs ((2 to_power (MajP n,(abs i))) + i)) mod (2 to_power (MajP n,(abs i))) =
(((2 to_power (MajP n,(abs i))) mod (2 to_power (MajP n,(abs i)))) + (i mod (2 to_power (MajP n,(abs i))))) mod (2 to_power (MajP n,(abs i)))
by INT_3:14
.=
(i mod (2 to_power (MajP n,(abs i)))) mod (2 to_power (MajP n,(abs i)))
by A10
;
hence
((abs ((2 to_power (MajP (n + 1),(abs i))) + i)) div (2 to_power (j -' 1))) mod 2
= ((abs ((2 to_power (MajP n,(abs i))) + i)) div (2 to_power (j -' 1))) mod 2
by A9, A12, Lm3;
verum
end;
per cases
( i >= 0 or i < 0 )
;
suppose
i >= 0
;
(2sComplement (n + 1),i) /. j = (2sComplement n,i) /. jthen reconsider i =
i as
Element of
NAT by INT_1:16;
A13:
(2sComplement n,i) /. j =
(n -BinarySequence (abs i)) /. j
by Def2
.=
(n -BinarySequence i) /. j
by ABSVALUE:def 1
.=
IFEQ ((i div (2 to_power (j -' 1))) mod 2),
0 ,
FALSE ,
TRUE
by A3, BINARI_3:def 1
;
(2sComplement (n + 1),i) /. j =
((n + 1) -BinarySequence (abs i)) /. j
by Def2
.=
((n + 1) -BinarySequence i) /. j
by ABSVALUE:def 1
.=
IFEQ ((i div (2 to_power (j -' 1))) mod 2),
0 ,
FALSE ,
TRUE
by A4, BINARI_3:def 1
;
hence
(2sComplement (n + 1),i) /. j = (2sComplement n,i) /. j
by A13;
verum end; suppose A14:
i < 0
;
(2sComplement (n + 1),i) /. j = (2sComplement n,i) /. jthen A15:
(2sComplement n,i) /. j =
(n -BinarySequence (abs ((2 to_power (MajP n,(abs i))) + i))) /. j
by Def2
.=
IFEQ (((abs ((2 to_power (MajP n,(abs i))) + i)) div (2 to_power (j -' 1))) mod 2),
0 ,
FALSE ,
TRUE
by A3, BINARI_3:def 1
;
(2sComplement (n + 1),i) /. j =
((n + 1) -BinarySequence (abs ((2 to_power (MajP (n + 1),(abs i))) + i))) /. j
by A14, Def2
.=
IFEQ (((abs ((2 to_power (MajP (n + 1),(abs i))) + i)) div (2 to_power (j -' 1))) mod 2),
0 ,
FALSE ,
TRUE
by A4, BINARI_3:def 1
;
hence
(2sComplement (n + 1),i) /. j = (2sComplement n,i) /. j
by A5, A14, A15;
verum end; end;