ex N being Element of NAT st
for n being Element of NAT st n >= N holds
n / 2 > (log 2,n) * (log 2,n)
proof
reconsider N = 2
to_power 10 as
Element of
NAT ;
now take N =
N;
for n being Element of NAT st n >= N holds
n / 2 > (log 2,n) * (log 2,n)let n be
Element of
NAT ;
( n >= N implies n / 2 > (log 2,n) * (log 2,n) )set x =
log 2,
n;
A1:
2
to_power 9
> 0
by POWER:39;
assume A2:
n >= N
;
n / 2 > (log 2,n) * (log 2,n)then A3:
n > 0
by POWER:39;
2
to_power 10
> 2
to_power 0
by POWER:44;
then
n > 2
to_power 0
by A2, XXREAL_0:2;
then
n > 1
by POWER:29;
then
log 2,
n > log 2,1
by POWER:65;
then
log 2,
n > 0
by POWER:59;
then
(log 2,n) * (log 2,n) > 0 * (log 2,n)
by XREAL_1:70;
then A4:
4
* ((log 2,n) * (log 2,n)) > 2
* ((log 2,n) * (log 2,n))
by XREAL_1:70;
2
to_power 10
> 2
to_power 1
by POWER:44;
then
n > 2
to_power 1
by A2, XXREAL_0:2;
then A5:
n > 2
by POWER:30;
then A6:
2
* n > 2
* 2
by XREAL_1:70;
n * n > 2
* n
by A5, XREAL_1:70;
then
n ^2 > 2
* 2
by A6, XXREAL_0:2;
then
log 2,
(n ^2 ) > log 2,
(2 ^2 )
by POWER:65;
then
log 2,
(n ^2 ) > log 2,
(2 to_power 2)
by POWER:53;
then
log 2,
(n ^2 ) > 2
* (log 2,2)
by POWER:63;
then A7:
log 2,
(n ^2 ) > 2
* 1
by POWER:60;
then A8:
(log 2,(n ^2 )) ^2 > 0
by SQUARE_1:74;
2
to_power 10
> 2
to_power 9
by POWER:44;
then
n > 2
to_power 9
by A2, XXREAL_0:2;
then
log 2,
n > log 2,
(2 to_power 9)
by A1, POWER:65;
then
log 2,
n > 9
* (log 2,2)
by POWER:63;
then A9:
log 2,
n > 9
* 1
by POWER:60;
then A10:
2
* (log 2,n) > 0 * (log 2,n)
by XREAL_1:70;
then
(2 * (log 2,n)) * (2 * (log 2,n)) > 0 * (2 * (log 2,n))
by XREAL_1:70;
then
log 2,
(2 to_power (log 2,n)) > log 2,
((2 * (log 2,n)) ^2 )
by A9, Lm31, POWER:65;
then
(log 2,n) * (log 2,2) > log 2,
((2 * (log 2,n)) ^2 )
by POWER:63;
then
(log 2,n) * 1
> log 2,
((2 * (log 2,n)) ^2 )
by POWER:60;
then
log 2,
n > log 2,
((2 * (log 2,n)) to_power 2)
by POWER:53;
then
log 2,
n > 2
* (log 2,(2 * (log 2,n)))
by A10, POWER:63;
then
log 2,
n > 2
* (log 2,(log 2,(n to_power 2)))
by A3, POWER:63;
then
log 2,
n > 2
* (log 2,(log 2,(n ^2 )))
by POWER:53;
then
2
to_power (log 2,n) > 2
to_power (2 * (log 2,(log 2,(n ^2 ))))
by POWER:44;
then
n > 2
to_power (2 * (log 2,(log 2,(n ^2 ))))
by A3, POWER:def 3;
then
n > 2
to_power (log 2,((log 2,(n ^2 )) to_power 2))
by A7, POWER:63;
then
n > 2
to_power (log 2,((log 2,(n ^2 )) ^2 ))
by POWER:53;
then
n > (log 2,(n ^2 )) ^2
by A8, POWER:def 3;
then
n > (log 2,(n to_power 2)) ^2
by POWER:53;
then
n > (2 * (log 2,n)) ^2
by A3, POWER:63;
then
n > 2
* ((log 2,n) * (log 2,n))
by A4, XXREAL_0:2;
hence
n / 2
> (log 2,n) * (log 2,n)
by XREAL_1:83;
verum end;
hence
ex
N being
Element of
NAT st
for
n being
Element of
NAT st
n >= N holds
n / 2
> (log 2,n) * (log 2,n)
;
verum
end;
then consider N3 being Element of NAT such that
A11:
for n being Element of NAT st n >= N3 holds
n / 2 > (log 2,n) * (log 2,n)
;
now take N = 30;
for n being Element of NAT st n >= N holds
n / 3 > 2 * (log 2,n)let n be
Element of
NAT ;
( n >= N implies n / 3 > 2 * (log 2,n) )assume A12:
n >= N
;
n / 3 > 2 * (log 2,n)then A13:
n to_power 6
> 0
by POWER:39;
2
to_power n > n to_power 6
by A12, Lm30;
then
log 2,
(2 to_power n) > log 2,
(n to_power 6)
by A13, POWER:65;
then
n * (log 2,2) > log 2,
(n to_power 6)
by POWER:63;
then
n * 1
> log 2,
(n to_power 6)
by POWER:60;
then
n > (3 * 2) * (log 2,n)
by A12, POWER:63;
then
n > 3
* (2 * (log 2,n))
;
hence
n / 3
> 2
* (log 2,n)
by XREAL_1:83;
verum end;
then consider N2 being Element of NAT such that
A14:
for n being Element of NAT st n >= N2 holds
n / 3 > 2 * (log 2,n)
;
then consider N1 being Element of NAT such that
A15:
for n being Element of NAT st n >= N1 holds
n / 6 > 1
;
set N = max (max N1,2),(max N2,N3);
A16:
max (max N1,2),(max N2,N3) >= max N1,2
by XXREAL_0:25;
max N1,2 >= 2
by XXREAL_0:25;
then A17:
max (max N1,2),(max N2,N3) >= 2
by A16, XXREAL_0:2;
A18:
max (max N1,2),(max N2,N3) >= max N2,N3
by XXREAL_0:25;
max N2,N3 >= N3
by XXREAL_0:25;
then A19:
max (max N1,2),(max N2,N3) >= N3
by A18, XXREAL_0:2;
max N2,N3 >= N2
by XXREAL_0:25;
then A20:
max (max N1,2),(max N2,N3) >= N2
by A18, XXREAL_0:2;
max N1,2 >= N1
by XXREAL_0:25;
then A21:
max (max N1,2),(max N2,N3) >= N1
by A16, XXREAL_0:2;
now let n be
Element of
NAT ;
( n >= max (max N1,2),(max N2,N3) implies (sqrt n) - (log 2,n) > 1 )A22:
(1 + (2 * (log 2,n))) + ((log 2,n) * (log 2,n)) = (1 + (log 2,n)) ^2
;
assume A23:
n >= max (max N1,2),
(max N2,N3)
;
(sqrt n) - (log 2,n) > 1then
n >= N2
by A20, XXREAL_0:2;
then A24:
n / 3
> 2
* (log 2,n)
by A14;
n >= 2
by A17, A23, XXREAL_0:2;
then
log 2,
n >= log 2,2
by PRE_FF:12;
then A25:
log 2,
n >= 1
by POWER:60;
n >= N1
by A21, A23, XXREAL_0:2;
then
n / 6
> 1
by A15;
then A26:
(n / 6) + (n / 3) > 1
+ (2 * (log 2,n))
by A24, XREAL_1:10;
n >= N3
by A19, A23, XXREAL_0:2;
then A27:
n / 2
> (log 2,n) * (log 2,n)
by A11;
((n / 6) + (n / 3)) + (n / 2) = n
;
then
n > (1 + (log 2,n)) ^2
by A26, A27, A22, XREAL_1:10;
then
sqrt n > sqrt ((1 + (log 2,n)) ^2 )
by SQUARE_1:95, XREAL_1:65;
then
sqrt n > 1
+ (log 2,n)
by A25, SQUARE_1:89;
hence
(sqrt n) - (log 2,n) > 1
by XREAL_1:22;
verum end;
hence
ex N being Element of NAT st
for n being Element of NAT st n >= N holds
(sqrt n) - (log 2,n) > 1
; verum