let A, N be non empty finite set ; for f being Function of (Funcs N,(LinOrders A)),(LinPreorders A) st ( for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A st ( for i being Element of N holds a <_ p . i,b ) holds
a <_ f . p,b ) & ( for p, p9 being Element of Funcs N,(LinOrders A)
for a, b being Element of A st ( for i being Element of N holds
( a <_ p . i,b iff a <_ p9 . i,b ) ) holds
( a <_ f . p,b iff a <_ f . p9,b ) ) & card A >= 3 holds
ex n being Element of N st
for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A holds
( a <_ p . n,b iff a <_ f . p,b )
let f be Function of (Funcs N,(LinOrders A)),(LinPreorders A); ( ( for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A st ( for i being Element of N holds a <_ p . i,b ) holds
a <_ f . p,b ) & ( for p, p9 being Element of Funcs N,(LinOrders A)
for a, b being Element of A st ( for i being Element of N holds
( a <_ p . i,b iff a <_ p9 . i,b ) ) holds
( a <_ f . p,b iff a <_ f . p9,b ) ) & card A >= 3 implies ex n being Element of N st
for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A holds
( a <_ p . n,b iff a <_ f . p,b ) )
assume that
A1:
for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A st ( for i being Element of N holds a <_ p . i,b ) holds
a <_ f . p,b
and
A2:
for p, p9 being Element of Funcs N,(LinOrders A)
for a, b being Element of A st ( for i being Element of N holds
( a <_ p . i,b iff a <_ p9 . i,b ) ) holds
( a <_ f . p,b iff a <_ f . p9,b )
and
A3:
card A >= 3
; ex n being Element of N st
for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A holds
( a <_ p . n,b iff a <_ f . p,b )
consider o being Element of LinOrders A;
defpred S1[ Element of LinPreorders A, Element of A, Element of A] means ( $2 <=_ $1,$3 & ( $2 <_ $1,$3 or $2 <=_ o,$3 ) );
defpred S2[ Element of LinPreorders A, Element of LinOrders A] means for a, b being Element of A holds
( S1[$1,a,b] iff a <=_ $2,b );
A4:
for o9 being Element of LinPreorders A ex o1 being Element of LinOrders A st S2[o9,o1]
proof
let o9 be
Element of
LinPreorders A;
ex o1 being Element of LinOrders A st S2[o9,o1]
defpred S3[
Element of
A,
Element of
A]
means S1[
o9,$1,$2];
consider o1 being
Relation of
A such that A5:
for
a,
b being
Element of
A holds
(
[a,b] in o1 iff
S3[
a,
b] )
from RELSET_1:sch 2();
A8:
now let a,
b,
c be
Element of
A;
( [a,b] in o1 & [b,c] in o1 implies [a,c] in o1 )A9:
(
S3[
a,
b] &
S3[
b,
c] implies
S3[
a,
c] )
by Th5;
thus
(
[a,b] in o1 &
[b,c] in o1 implies
[a,c] in o1 )
by A5, A9;
verum end;
reconsider o1 =
o1 as
Element of
LinPreorders A by A6, A8, Def1;
A10:
now let a,
b be
Element of
A;
( [a,b] in o1 & [b,a] in o1 implies a = b )A11:
(
S3[
a,
b] &
S3[
b,
a] implies
a = b )
by Th6;
thus
(
[a,b] in o1 &
[b,a] in o1 implies
a = b )
by A5, A11;
verum end;
reconsider o1 =
o1 as
Element of
LinOrders A by A10, Def2;
take
o1
;
S2[o9,o1]
let a,
b be
Element of
A;
( S1[o9,a,b] iff a <=_ o1,b )
A12:
(
[a,b] in o1 iff
S3[
a,
b] )
by A5;
thus
(
S1[
o9,
a,
b] iff
a <=_ o1,
b )
by A12, Def4;
verum
end;
defpred S3[ Element of Funcs N,(LinPreorders A), Element of Funcs N,(LinOrders A)] means for i being Element of N holds S2[$1 . i,$2 . i];
A13:
for q being Element of Funcs N,(LinPreorders A)
for p, p9 being Element of Funcs N,(LinOrders A) st S3[q,p] & S3[q,p9] holds
p = p9
proof
let q be
Element of
Funcs N,
(LinPreorders A);
for p, p9 being Element of Funcs N,(LinOrders A) st S3[q,p] & S3[q,p9] holds
p = p9let p,
p9 be
Element of
Funcs N,
(LinOrders A);
( S3[q,p] & S3[q,p9] implies p = p9 )
assume that A14:
S3[
q,
p]
and A15:
S3[
q,
p9]
;
p = p9
let i be
Element of
N;
FUNCT_2:def 9 p . i = p9 . i
reconsider pi =
p . i as
Relation of
A by Def1;
reconsider pi9 =
p9 . i as
Relation of
A by Def1;
A16:
now let a,
b be
Element of
A;
( [a,b] in p . i iff [a,b] in p9 . i )A17:
(
S1[
q . i,
a,
b] iff
a <=_ p . i,
b )
by A14;
A18:
(
S1[
q . i,
a,
b] iff
a <=_ p9 . i,
b )
by A15;
thus
(
[a,b] in p . i iff
[a,b] in p9 . i )
by A17, A18, Def4;
verum end;
A19:
pi = pi9
by A16, RELSET_1:def 3;
thus
p . i = p9 . i
by A19;
verum
end;
A20:
for q being Element of Funcs N,(LinPreorders A) ex p being Element of Funcs N,(LinOrders A) st S3[q,p]
proof
let q be
Element of
Funcs N,
(LinPreorders A);
ex p being Element of Funcs N,(LinOrders A) st S3[q,p]
defpred S4[
Element of
N,
Element of
LinOrders A]
means S2[
q . $1,$2];
A21:
for
i being
Element of
N ex
o1 being
Element of
LinOrders A st
S4[
i,
o1]
by A4;
consider p being
Function of
N,
(LinOrders A) such that A22:
for
i being
Element of
N holds
S4[
i,
p . i]
from FUNCT_2:sch 3(A21);
reconsider p =
p as
Element of
Funcs N,
(LinOrders A) by FUNCT_2:11;
take
p
;
S3[q,p]
thus
S3[
q,
p]
by A22;
verum
end;
defpred S4[ Element of Funcs N,(LinPreorders A), Element of LinPreorders A] means ex p being Element of Funcs N,(LinOrders A) st
( S3[$1,p] & f . p = $2 );
A23:
for q being Element of Funcs N,(LinPreorders A) ex o9 being Element of LinPreorders A st S4[q,o9]
consider f9 being Function of (Funcs N,(LinPreorders A)),(LinPreorders A) such that
A25:
for q being Element of Funcs N,(LinPreorders A) holds S4[q,f9 . q]
from FUNCT_2:sch 3(A23);
A26:
for q being Element of Funcs N,(LinPreorders A)
for a, b being Element of A st ( for i being Element of N holds a <_ q . i,b ) holds
a <_ f9 . q,b
proof
let q be
Element of
Funcs N,
(LinPreorders A);
for a, b being Element of A st ( for i being Element of N holds a <_ q . i,b ) holds
a <_ f9 . q,blet a,
b be
Element of
A;
( ( for i being Element of N holds a <_ q . i,b ) implies a <_ f9 . q,b )
assume A27:
for
i being
Element of
N holds
a <_ q . i,
b
;
a <_ f9 . q,b
consider p being
Element of
Funcs N,
(LinOrders A) such that A28:
S3[
q,
p]
and A29:
f . p = f9 . q
by A25;
thus
a <_ f9 . q,
b
by A1, A29, A30;
verum
end;
A32:
now let q,
q9 be
Element of
Funcs N,
(LinPreorders A);
for a, b being Element of A st ( for i being Element of N holds
( ( a <_ q . i,b implies a <_ q9 . i,b ) & ( a <_ q9 . i,b implies a <_ q . i,b ) & ( b <_ q . i,a implies b <_ q9 . i,a ) & ( b <_ q9 . i,a implies b <_ q . i,a ) ) ) holds
( a <_ f9 . q,b iff a <_ f9 . q9,b )let a,
b be
Element of
A;
( ( for i being Element of N holds
( ( a <_ q . i,b implies a <_ q9 . i,b ) & ( a <_ q9 . i,b implies a <_ q . i,b ) & ( b <_ q . i,a implies b <_ q9 . i,a ) & ( b <_ q9 . i,a implies b <_ q . i,a ) ) ) implies ( a <_ f9 . q,b iff a <_ f9 . q9,b ) )assume A33:
for
i being
Element of
N holds
( (
a <_ q . i,
b implies
a <_ q9 . i,
b ) & (
a <_ q9 . i,
b implies
a <_ q . i,
b ) & (
b <_ q . i,
a implies
b <_ q9 . i,
a ) & (
b <_ q9 . i,
a implies
b <_ q . i,
a ) )
;
( a <_ f9 . q,b iff a <_ f9 . q9,b )consider p being
Element of
Funcs N,
(LinOrders A) such that A34:
S3[
q,
p]
and A35:
f . p = f9 . q
by A25;
consider p9 being
Element of
Funcs N,
(LinOrders A) such that A36:
S3[
q9,
p9]
and A37:
f . p9 = f9 . q9
by A25;
A38:
for
i being
Element of
N holds
(
a <_ p . i,
b iff
a <_ p9 . i,
b )
proof
let i be
Element of
N;
( a <_ p . i,b iff a <_ p9 . i,b )
A39:
(
S1[
q . i,
b,
a] iff
S1[
q9 . i,
b,
a] )
by A33;
thus
(
a <_ p . i,
b iff
a <_ p9 . i,
b )
by A34, A36, A39;
verum
end; thus
(
a <_ f9 . q,
b iff
a <_ f9 . q9,
b )
by A2, A35, A37, A38;
verum end;
consider n being Element of N such that
A40:
for q being Element of Funcs N,(LinPreorders A)
for a, b being Element of A st a <_ q . n,b holds
a <_ f9 . q,b
by A3, A26, A32, Th14;
take
n
; for p being Element of Funcs N,(LinOrders A)
for a, b being Element of A holds
( a <_ p . n,b iff a <_ f . p,b )
let p be Element of Funcs N,(LinOrders A); for a, b being Element of A holds
( a <_ p . n,b iff a <_ f . p,b )
A41:
now A42:
rng p c= LinOrders A
by RELAT_1:def 19;
A43:
(
dom p = N &
rng p c= LinPreorders A )
by A42, FUNCT_2:def 1, XBOOLE_1:1;
reconsider q =
p as
Element of
Funcs N,
(LinPreorders A) by A43, FUNCT_2:def 2;
A44:
S3[
q,
p]
proof
let i be
Element of
N;
S2[q . i,p . i]let a,
b be
Element of
A;
( S1[q . i,a,b] iff a <=_ p . i,b )
A45:
(
a <_ p . i,
b or
a = b or
a >_ p . i,
b )
by Th6;
thus
(
S1[
q . i,
a,
b] iff
a <=_ p . i,
b )
by A45, Th4;
verum
end; A46:
ex
p9 being
Element of
Funcs N,
(LinOrders A) st
(
S3[
q,
p9] &
f . p9 = f9 . q )
by A25;
let a,
b be
Element of
A;
( a <_ p . n,b implies a <_ f . p,b )assume A47:
a <_ p . n,
b
;
a <_ f . p,bA48:
a <_ f9 . q,
b
by A40, A47;
thus
a <_ f . p,
b
by A13, A44, A46, A48;
verum end;
thus
for a, b being Element of A holds
( a <_ p . n,b iff a <_ f . p,b )
by A41, Th13; verum