let S be non empty set ; for T being Subset of S
for A being free ECIW-strict preIfWhileAlgebra
for f1, f2 being ExecutionFunction of A,S,T st f1 | [:S,(ElementaryInstructions A):] = f2 | [:S,(ElementaryInstructions A):] & ( for s being Element of S
for C, I being Element of A st not f1 iteration_terminates_for I \; C,f1 . s,C holds
f1 . s,(while C,I) = f2 . s,(while C,I) ) holds
f1 = f2
let T be Subset of S; for A being free ECIW-strict preIfWhileAlgebra
for f1, f2 being ExecutionFunction of A,S,T st f1 | [:S,(ElementaryInstructions A):] = f2 | [:S,(ElementaryInstructions A):] & ( for s being Element of S
for C, I being Element of A st not f1 iteration_terminates_for I \; C,f1 . s,C holds
f1 . s,(while C,I) = f2 . s,(while C,I) ) holds
f1 = f2
let A be free ECIW-strict preIfWhileAlgebra; for f1, f2 being ExecutionFunction of A,S,T st f1 | [:S,(ElementaryInstructions A):] = f2 | [:S,(ElementaryInstructions A):] & ( for s being Element of S
for C, I being Element of A st not f1 iteration_terminates_for I \; C,f1 . s,C holds
f1 . s,(while C,I) = f2 . s,(while C,I) ) holds
f1 = f2
let f1, f2 be ExecutionFunction of A,S,T; ( f1 | [:S,(ElementaryInstructions A):] = f2 | [:S,(ElementaryInstructions A):] & ( for s being Element of S
for C, I being Element of A st not f1 iteration_terminates_for I \; C,f1 . s,C holds
f1 . s,(while C,I) = f2 . s,(while C,I) ) implies f1 = f2 )
assume A1:
f1 | [:S,(ElementaryInstructions A):] = f2 | [:S,(ElementaryInstructions A):]
; ( ex s being Element of S ex C, I being Element of A st
( not f1 iteration_terminates_for I \; C,f1 . s,C & not f1 . s,(while C,I) = f2 . s,(while C,I) ) or f1 = f2 )
set g = f1 | [:S,(ElementaryInstructions A):];
assume A2:
for s being Element of S
for C, I being Element of A st not f1 iteration_terminates_for I \; C,f1 . s,C holds
f1 . s,(while C,I) = f2 . s,(while C,I)
; f1 = f2
defpred S1[ set ] means for s being Element of S holds f1 . s,$1 = f2 . s,$1;
A3:
for I being Element of A st I in ElementaryInstructions A holds
S1[I]
proof
let I be
Element of
A;
( I in ElementaryInstructions A implies S1[I] )
assume A4:
I in ElementaryInstructions A
;
S1[I]
let s be
Element of
S;
f1 . s,I = f2 . s,I
A5:
[s,I] in [:S,(ElementaryInstructions A):]
by A4, ZFMISC_1:106;
hence f1 . s,
I =
(f1 | [:S,(ElementaryInstructions A):]) . [s,I]
by FUNCT_1:72
.=
f2 . s,
I
by A1, A5, FUNCT_1:72
;
verum
end;
A6:
S1[ EmptyIns A]
A7:
for I1, I2 being Element of A st S1[I1] & S1[I2] holds
S1[I1 \; I2]
proof
let I1,
I2 be
Element of
A;
( S1[I1] & S1[I2] implies S1[I1 \; I2] )
assume that A8:
S1[
I1]
and A9:
S1[
I2]
;
S1[I1 \; I2]
let s be
Element of
S;
f1 . s,(I1 \; I2) = f2 . s,(I1 \; I2)
thus f1 . s,
(I1 \; I2) =
f1 . (f1 . s,I1),
I2
by Def29
.=
f1 . (f2 . s,I1),
I2
by A8
.=
f2 . (f2 . s,I1),
I2
by A9
.=
f2 . s,
(I1 \; I2)
by Def29
;
verum
end;
A10:
for C, I1, I2 being Element of A st S1[C] & S1[I1] & S1[I2] holds
S1[ if-then-else C,I1,I2]
proof
let C,
I1,
I2 be
Element of
A;
( S1[C] & S1[I1] & S1[I2] implies S1[ if-then-else C,I1,I2] )
assume that A11:
S1[
C]
and A12:
S1[
I1]
and A13:
S1[
I2]
;
S1[ if-then-else C,I1,I2]
let s be
Element of
S;
f1 . s,(if-then-else C,I1,I2) = f2 . s,(if-then-else C,I1,I2)
A14:
f1 complies_with_if_wrt T
by Def32;
A15:
f2 complies_with_if_wrt T
by Def32;
A16:
f1 . s,
C = f2 . s,
C
by A11;
per cases
( f1 . s,C in T or f1 . s,C nin T )
;
suppose A17:
f1 . s,
C in T
;
f1 . s,(if-then-else C,I1,I2) = f2 . s,(if-then-else C,I1,I2)hence f1 . s,
(if-then-else C,I1,I2) =
f1 . (f1 . s,C),
I1
by A14, Def30
.=
f2 . (f1 . s,C),
I1
by A12
.=
f2 . s,
(if-then-else C,I1,I2)
by A15, A16, A17, Def30
;
verum end; suppose A18:
f1 . s,
C nin T
;
f1 . s,(if-then-else C,I1,I2) = f2 . s,(if-then-else C,I1,I2)hence f1 . s,
(if-then-else C,I1,I2) =
f1 . (f1 . s,C),
I2
by A14, Def30
.=
f2 . (f1 . s,C),
I2
by A13
.=
f2 . s,
(if-then-else C,I1,I2)
by A15, A16, A18, Def30
;
verum end; end;
end;
A19:
for C, I being Element of A st S1[C] & S1[I] holds
S1[ while C,I]
proof
let C,
I be
Element of
A;
( S1[C] & S1[I] implies S1[ while C,I] )
assume that A20:
S1[
C]
and A21:
S1[
I]
;
S1[ while C,I]
let s be
Element of
S;
f1 . s,(while C,I) = f2 . s,(while C,I)
now assume
f1 iteration_terminates_for I \; C,
f1 . s,
C
;
f1 . s,(while C,I) = f2 . s,(while C,I)then consider r being non
empty FinSequence of
S such that A22:
r . 1
= f1 . s,
C
and A23:
r . (len r) nin T
and A24:
for
i being
Nat st 1
<= i &
i < len r holds
(
r . i in T &
r . (i + 1) = f1 . (r . i),
(I \; C) )
by Def33;
A25:
f1 . s,
C = f2 . s,
C
by A20;
A26:
now let i be
Nat;
( 1 <= i & i < len r implies ( r . i in T & r . (i + 1) = f2 . (r . i),(I \; C) ) )assume that A27:
1
<= i
and A28:
i < len r
;
( r . i in T & r . (i + 1) = f2 . (r . i),(I \; C) )thus
r . i in T
by A24, A27, A28;
r . (i + 1) = f2 . (r . i),(I \; C)then reconsider si =
r . i as
Element of
S ;
thus r . (i + 1) =
f1 . si,
(I \; C)
by A24, A27, A28
.=
f1 . (f1 . si,I),
C
by Def29
.=
f1 . (f2 . si,I),
C
by A21
.=
f2 . (f2 . si,I),
C
by A20
.=
f2 . (r . i),
(I \; C)
by Def29
;
verum end; thus f1 . s,
(while C,I) =
r . (len r)
by A22, A23, A24, Th86
.=
f2 . s,
(while C,I)
by A22, A23, A25, A26, Th86
;
verum end;
hence
f1 . s,
(while C,I) = f2 . s,
(while C,I)
by A2;
verum
end;
hence
f1 = f2
by FUNCT_2:113; verum