let a, b, x, y, x', y' be set ; ( a <> b & a,b --> x,y = a,b --> x',y' implies ( x = x' & y = y' ) )
assume that
A1:
a <> b
and
A2:
a,b --> x,y = a,b --> x',y'
; ( x = x' & y = y' )
thus x =
(a,b --> x,y) . a
by A1, Th66
.=
x'
by A1, A2, Th66
; y = y'
thus y =
(a,b --> x,y) . b
by Th66
.=
y'
by A2, Th66
; verum