let x, y, A be set ; ( <*x,y*> - A = <*x,y*> iff ( not x in A & not y in A ) )
A1:
<*x,y*> = <*x*> ^ <*y*>
by FINSEQ_1:def 9;
thus
( <*x,y*> - A = <*x,y*> implies ( not x in A & not y in A ) )
( not x in A & not y in A implies <*x,y*> - A = <*x,y*> )proof
assume A2:
<*x,y*> - A = <*x,y*>
;
( not x in A & not y in A )
assume
(
x in A or
y in A )
;
contradiction
then
( (
x in A &
y in A ) or ( not
x in A &
y in A ) or (
x in A & not
y in A ) )
;
then
(
<*x,y*> - A = {} or
<*x,y*> - A = <*x*> or
<*x,y*> - A = <*y*> )
by Th84, Th85, Th87;
hence
contradiction
by A2, Th40, CARD_1:47, FINSEQ_1:61;
verum
end;
assume that
A3:
not x in A
and
A4:
not y in A
; <*x,y*> - A = <*x,y*>
A5:
<*y*> - A = <*y*>
by A4, Lm6;
<*x*> - A = <*x*>
by A3, Lm6;
hence
<*x,y*> - A = <*x,y*>
by A5, A1, Lm11; verum