let X be BCI-algebra; for Y being SubAlgebra of X
for x, y being Element of
for x', y' being Element of st x = x' & y = y' holds
x \ y = x' \ y'
let Y be SubAlgebra of X; for x, y being Element of
for x', y' being Element of st x = x' & y = y' holds
x \ y = x' \ y'
let x, y be Element of ; for x', y' being Element of st x = x' & y = y' holds
x \ y = x' \ y'
let x', y' be Element of ; ( x = x' & y = y' implies x \ y = x' \ y' )
assume A1:
( x = x' & y = y' )
; x \ y = x' \ y'
A2:
[x',y'] in [:the carrier of Y,the carrier of Y:]
by ZFMISC_1:106;
x' \ y' =
(the InternalDiff of X || the carrier of Y) . x',y'
by BCIALG_1:def 10
.=
x \ y
by A1, A2, FUNCT_1:72
;
hence
x \ y = x' \ y'
; verum