let X be set ; for F being Dependency-set of X holds
( F is (F1) & F is (F2) & F is (F3) & F is (F4) iff ( F is (F1) & F is (DC5) & F is (DC6) ) )
let F be Dependency-set of X; ( F is (F1) & F is (F2) & F is (F3) & F is (F4) iff ( F is (F1) & F is (DC5) & F is (DC6) ) )
hereby ( F is (F1) & F is (DC5) & F is (DC6) implies ( F is (F1) & F is (F2) & F is (F3) & F is (F4) ) )
assume that A1:
F is
(F1)
and A2:
F is
(F2)
and A3:
F is
(F3)
and A4:
F is
(F4)
;
( F is (F1) & F is (DC5) & F is (DC6) )thus
F is
(F1)
by A1;
( F is (DC5) & F is (DC6) )thus
F is
(DC5)
F is (DC6) proof
let A,
B,
C,
D be
Subset of ;
ARMSTRNG:def 30 ( [A,B] in F & [(B \/ C),D] in F implies [(A \/ C),D] in F )
assume that A5:
[A,B] in F
and A6:
[(B \/ C),D] in F
;
[(A \/ C),D] in F
[C,C] in F
by A1, Def12;
then
[(A \/ C),(B \/ C)] in F
by A4, A5, Def14;
hence
[(A \/ C),D] in F
by A2, A6, Th20;
verum
end; thus
F is
(DC6)
verumproof
let A,
B,
C be
Subset of ;
ARMSTRNG:def 31 ( [A,B] in F implies [(A \/ C),B] in F )
assume A7:
[A,B] in F
;
[(A \/ C),B] in F
A c= A \/ C
by XBOOLE_1:7;
then
[(A \/ C),A] in F
by A1, A3, Def16;
hence
[(A \/ C),B] in F
by A2, A7, Th20;
verum
end;
end;
assume that
A8:
F is (F1)
and
A9:
F is (DC5)
and
A10:
F is (DC6)
; ( F is (F1) & F is (F2) & F is (F3) & F is (F4) )
thus
F is (F1)
by A8; ( F is (F2) & F is (F3) & F is (F4) )
A11:
now let A,
B,
C be
Subset of ;
( [A,B] in F & [B,C] in F implies [A,C] in F )assume that A12:
[A,B] in F
and A13:
[B,C] in F
;
[A,C] in F
[(B \/ A),C] in F
by A10, A13, Def31;
then
[(A \/ A),C] in F
by A9, A12, Def30;
hence
[A,C] in F
;
verum end;
hence
F is (F2)
by Th20; ( F is (F3) & F is (F4) )
thus
F is (F3)
F is (F4) proof
let A,
B,
A',
B' be
Subset of ;
ARMSTRNG:def 13 ( [A,B] in F & [A,B] >= [A',B'] implies [A',B'] in F )
assume that A14:
[A,B] in F
and A15:
[A,B] >= [A',B']
;
[A',B'] in F
A c= A'
by A15, Th15;
then
A' = A \/ (A' \ A)
by XBOOLE_1:45;
then A16:
[A',B] in F
by A10, A14, Def31;
B' c= B
by A15, Th15;
then A17:
B = B' \/ (B \ B')
by XBOOLE_1:45;
[B',B'] in F
by A8, Def12;
then
[B,B'] in F
by A10, A17, Def31;
hence
[A',B'] in F
by A11, A16;
verum
end;
let A, B, A', B' be Subset of ; ARMSTRNG:def 14 ( [A,B] in F & [A',B'] in F implies [(A \/ A'),(B \/ B')] in F )
assume that
A18:
[A,B] in F
and
A19:
[A',B'] in F
; [(A \/ A'),(B \/ B')] in F
[(B \/ B'),(B \/ B')] in F
by A8, Def12;
then
[(A \/ B'),(B \/ B')] in F
by A9, A18, Def30;
hence
[(A \/ A'),(B \/ B')] in F
by A9, A19, Def30; verum