set p = 1;
set q = 2;
let i be Instruction of ; ( ( for l being Instruction-Location of SCM holds NIC i,l = {(Next )} ) implies JUMP i is empty )
assume A1:
for l being Instruction-Location of SCM holds NIC i,l = {(Next )}
; JUMP i is empty
set X = { (NIC i,f) where f is Instruction-Location of SCM : verum } ;
reconsider p = 1, q = 2 as Instruction-Location of SCM by AMI_1:def 4;
assume
not JUMP i is empty
; contradiction
then consider x being set such that
A2:
x in meet { (NIC i,f) where f is Instruction-Location of SCM : verum }
by XBOOLE_0:def 1;
NIC i,p = {(Next )}
by A1;
then
{(Next )} in { (NIC i,f) where f is Instruction-Location of SCM : verum }
;
then
x in {(Next )}
by A2, SETFAM_1:def 1;
then A3:
x = Next
by TARSKI:def 1;
NIC i,q = {(Next )}
by A1;
then
{(Next )} in { (NIC i,f) where f is Instruction-Location of SCM : verum }
;
then
x in {(Next )}
by A2, SETFAM_1:def 1;
hence
contradiction
by A3, TARSKI:def 1; verum