let L be non empty addLoopStr ; :: thesis: for a being Element of st ( for a being Element of holds a + (0. L) = a ) & ( for a being Element of ex x being Element of st a + x = 0. L ) & ( for a, b, c being Element of holds (a + b) + c = a + (b + c) ) holds
(0. L) + a = a + (0. L)
let a be Element of ; :: thesis: ( ( for a being Element of holds a + (0. L) = a ) & ( for a being Element of ex x being Element of st a + x = 0. L ) & ( for a, b, c being Element of holds (a + b) + c = a + (b + c) ) implies (0. L) + a = a + (0. L) )
assume that
A1: for a being Element of holds a + (0. L) = a and
A2: for a being Element of ex x being Element of st a + x = 0. L and
A3: for a, b, c being Element of holds (a + b) + c = a + (b + c) ; :: thesis: (0. L) + a = a + (0. L)
consider x being Element of such that
A4: a + x = 0. L by A2;
thus (0. L) + a = a + (x + a) by A3, A4
.= a + (0. L) by A1, A2, A3, A4, Th1 ; :: thesis: verum