let AP be AffinPlane; ( AP is satisfying_PPAP iff ( AP is Pappian & AP is satisfying_pap ) )
A1:
( AP is Pappian & AP is satisfying_pap implies AP is satisfying_PPAP )
proof
assume that A2:
AP is
Pappian
and A3:
AP is
satisfying_pap
;
AP is satisfying_PPAP
thus
AP is
satisfying_PPAP
verumproof
let M be
Subset of ;
AFF_2:def 1 for N being Subset of
for a, b, c, a', b', c' being Element of st M is being_line & N is being_line & a in M & b in M & c in M & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let N be
Subset of ;
for a, b, c, a', b', c' being Element of st M is being_line & N is being_line & a in M & b in M & c in M & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let a,
b,
c,
a',
b',
c' be
Element of ;
( M is being_line & N is being_line & a in M & b in M & c in M & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' implies a,c' // c,a' )
assume that A4:
M is
being_line
and A5:
N is
being_line
and A6:
a in M
and A7:
b in M
and A8:
c in M
and A9:
a' in N
and A10:
b' in N
and A11:
c' in N
and A12:
a,
b' // b,
a'
and A13:
b,
c' // c,
b'
;
a,c' // c,a'
now assume A14:
M <> N
;
( not a,c' // c,a' implies a,c' // c,a' )assume A15:
not
a,
c' // c,
a'
;
a,c' // c,a'now assume
not
M // N
;
a,c' // c,a'then consider o being
Element of
such that A16:
o in M
and A17:
o in N
by A4, A5, AFF_1:72;
A18:
o <> a
proof
assume A19:
o = a
;
contradiction
then
o,
b' // a',
b
by A12, AFF_1:13;
then
(
o = b' or
b in N )
by A5, A9, A10, A17, AFF_1:62;
then
(
o = b' or
o = b )
by A4, A5, A7, A14, A16, A17, AFF_1:30;
then
(
c,
o // b,
c' or
o,
c' // b',
c )
by A13, AFF_1:13;
then
(
c' in M or
c = o or
c in N or
o = c' )
by A4, A5, A7, A8, A10, A11, A16, A17, AFF_1:62;
then
(
o = c or
o = c' )
by A4, A5, A8, A11, A14, A16, A17, AFF_1:30;
hence
contradiction
by A5, A9, A11, A15, A17, A19, AFF_1:12, AFF_1:65;
verum
end; A20:
o <> b
proof
assume A21:
o = b
;
contradiction
then
o,
c' // b',
c
by A13, AFF_1:13;
then
(
o = c' or
c in N )
by A5, A10, A11, A17, AFF_1:62;
then A22:
(
o = c' or
o = c )
by A4, A5, A8, A14, A16, A17, AFF_1:30;
o,
a' // b',
a
by A12, A21, AFF_1:13;
then
(
o = a' or
a in N )
by A5, A9, A10, A17, AFF_1:62;
hence
contradiction
by A4, A5, A6, A8, A14, A15, A16, A17, A18, A22, AFF_1:12, AFF_1:30, AFF_1:65;
verum
end; A23:
o <> c'
proof
assume A24:
o = c'
;
contradiction
then
b' in M
by A4, A7, A8, A13, A16, A20, AFF_1:62;
then
a,
o // b,
a'
by A4, A5, A10, A12, A14, A16, A17, AFF_1:30;
then
a' in M
by A4, A6, A7, A16, A18, AFF_1:62;
hence
contradiction
by A4, A6, A8, A15, A16, A24, AFF_1:65;
verum
end; A25:
o <> c
proof
assume A26:
o = c
;
contradiction
then
o,
b' // c',
b
by A13, AFF_1:13;
then
(
o = b' or
b in N )
by A5, A10, A11, A17, AFF_1:62;
then
a' in M
by A4, A5, A6, A7, A9, A12, A16, A17, A18, A20, AFF_1:30, AFF_1:62;
then
a' = o
by A4, A5, A9, A14, A16, A17, AFF_1:30;
hence
contradiction
by A15, A26, AFF_1:12;
verum
end; A27:
o <> a'
proof
assume A28:
o = a'
;
contradiction
then
o,
b // a,
b'
by A12, AFF_1:13;
then
b' in M
by A4, A6, A7, A16, A20, AFF_1:62;
then
o = b'
by A4, A5, A10, A14, A16, A17, AFF_1:30;
then
c,
o // b,
c'
by A13, AFF_1:13;
then
c' in M
by A4, A7, A8, A16, A25, AFF_1:62;
hence
contradiction
by A4, A6, A8, A15, A16, A28, AFF_1:65;
verum
end;
o <> b'
proof
assume A29:
o = b'
;
contradiction
then
o,
c // b,
c'
by A13, AFF_1:13;
then A30:
c' in M
by A4, A7, A8, A16, A25, AFF_1:62;
a' in M
by A4, A6, A7, A12, A16, A18, A29, AFF_1:62;
hence
contradiction
by A4, A6, A8, A15, A30, AFF_1:65;
verum
end; hence
a,
c' // c,
a'
by A2, A4, A5, A6, A7, A8, A9, A10, A11, A12, A13, A14, A16, A17, A18, A20, A25, A27, A23, Def2;
verum end; hence
a,
c' // c,
a'
by A3, A4, A5, A6, A7, A8, A9, A10, A11, A12, A13, A14, Def13;
verum end;
hence
a,
c' // c,
a'
by A4, A6, A8, A9, A11, AFF_1:65;
verum
end;
end;
( AP is satisfying_PPAP implies ( AP is Pappian & AP is satisfying_pap ) )
proof
assume A31:
AP is
satisfying_PPAP
;
( AP is Pappian & AP is satisfying_pap )
thus
AP is
Pappian
AP is satisfying_pap proof
let M be
Subset of ;
AFF_2:def 2 for N being Subset of
for o, a, b, c, a', b', c' being Element of st M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a' & o <> b & o <> b' & o <> c & o <> c' & a in M & b in M & c in M & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let N be
Subset of ;
for o, a, b, c, a', b', c' being Element of st M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a' & o <> b & o <> b' & o <> c & o <> c' & a in M & b in M & c in M & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let o,
a,
b,
c,
a',
b',
c' be
Element of ;
( M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a' & o <> b & o <> b' & o <> c & o <> c' & a in M & b in M & c in M & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' implies a,c' // c,a' )
assume that A32:
(
M is
being_line &
N is
being_line )
and
M <> N
and
o in M
and
o in N
and
o <> a
and
o <> a'
and
o <> b
and
o <> b'
and
o <> c
and
o <> c'
and A33:
(
a in M &
b in M &
c in M &
a' in N &
b' in N &
c' in N &
a,
b' // b,
a' &
b,
c' // c,
b' )
;
a,c' // c,a'
thus
a,
c' // c,
a'
by A31, A32, A33, Def1;
verum
end;
thus
AP is
satisfying_pap
verumproof
let M be
Subset of ;
AFF_2:def 13 for N being Subset of
for a, b, c, a', b', c' being Element of st M is being_line & N is being_line & a in M & b in M & c in M & M // N & M <> N & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let N be
Subset of ;
for a, b, c, a', b', c' being Element of st M is being_line & N is being_line & a in M & b in M & c in M & M // N & M <> N & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let a,
b,
c,
a',
b',
c' be
Element of ;
( M is being_line & N is being_line & a in M & b in M & c in M & M // N & M <> N & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' implies a,c' // c,a' )
assume that A34:
(
M is
being_line &
N is
being_line &
a in M &
b in M &
c in M )
and
M // N
and
M <> N
and A35:
(
a' in N &
b' in N &
c' in N &
a,
b' // b,
a' &
b,
c' // c,
b' )
;
a,c' // c,a'
thus
a,
c' // c,
a'
by A31, A34, A35, Def1;
verum
end;
end;
hence
( AP is satisfying_PPAP iff ( AP is Pappian & AP is satisfying_pap ) )
by A1; verum