reconsider A0 = A1 \/ A2 as non emptySubset of A ; let F, G be Function of (A1 \/ A2),B; :: thesis: ( F | A1 = f1 & F | A2 = f2 & G | A1 = f1 & G | A2 = f2 implies F = G ) assume that A19:
F | A1 = f1
and A20:
F | A2 = f2
and A21:
G | A1 = f1
and A22:
G | A2 = f2
; :: thesis: F = G