let Y1, Y2 be set ; :: thesis: ( ( for y being set holds ( y in Y1 iff ex x being set st [x,y]in R ) ) & ( for y being set holds ( y in Y2 iff ex x being set st [x,y]in R ) ) implies Y1 = Y2 ) assume that A2:
for y being set holds ( y in Y1 iff ex x being set st [x,y]in R )
and A3:
for y being set holds ( y in Y2 iff ex x being set st [x,y]in R )
; :: thesis: Y1 = Y2