let S1, S2 be ExtREAL_sequence; :: thesis: ( ( for n being Nat holds S1 . n = (H . n) . x ) & ( for n being Nat holds S2 . n = (H . n) . x ) implies S1 = S2 )
assume that
A2: for n being Nat holds S1 . n = (H . n) . x and
A3: for n being Nat holds S2 . n = (H . n) . x ; :: thesis: S1 = S2

now

let n be Element of NAT ; :: thesis: S1 . n = S2 . n
S1 . n = (H . n) . x by A2;
hence S1 . n = S2 . n by A3; :: thesis: verum

end;

hence S1 = S2 by FUNCT_2:113; :: thesis: verum