let IT1, IT2 be Element of NAT ; :: thesis: ( f . IT1 = b & ( for i being Element of NAT st f . i = b holds IT1 <= i ) & f . IT2 = b & ( for i being Element of NAT st f . i = b holds IT2 <= i ) implies IT1 = IT2 ) assume that A6:
f . IT1 = b
and A7:
for i being Element of NAT st f . i = b holds IT1 <= i
and A8:
f . IT2 = b
and A9:
for i being Element of NAT st f . i = b holds IT2 <= i
; :: thesis: IT1 = IT2 assume A10:
IT1 <> IT2
; :: thesis: contradiction