let a, b be real number ; :: thesis: ( a < 0 & a < b implies b / a < 1 )
assume A1: a < 0 ; :: thesis: ( not a < b or b / a < 1 )
assume A2: a < b ; :: thesis: b / a < 1
assume b / a >= 1 ; :: thesis: contradiction
then (b / a) * a <= 1 * a by A1, Lm31;
hence contradiction by A1, A2, XCMPLX_1:88; :: thesis: verum