let S, T be complete LATTICE; :: thesis: for f being sups-preserving Function of S,T st T is meet-continuous & f is meet-preserving & f is one-to-one holds
S is meet-continuous
let f be sups-preserving Function of S,T; :: thesis: ( T is meet-continuous & f is meet-preserving & f is one-to-one implies S is meet-continuous )
assume that
A1:
T is meet-continuous
and
A2:
( f is meet-preserving & f is one-to-one )
; :: thesis: S is meet-continuous
A3:
T is meet-continuous LATTICE
by A1;
S is satisfying_MC
proof
let x be
Element of
S;
:: according to WAYBEL_2:def 6 :: thesis: for b1 being Element of bool the carrier of S holds x "/\" ("\/" b1,S) = "\/" ({x} "/\" b1),Slet D be non
empty directed Subset of
S;
:: thesis: x "/\" ("\/" D,S) = "\/" ({x} "/\" D),S
A4:
(
dom f = the
carrier of
S &
rng f c= the
carrier of
T )
by FUNCT_2:def 1;
A5:
(
ex_sup_of D,
S &
f preserves_sup_of D )
by WAYBEL_0:75, WAYBEL_0:def 33;
reconsider Y =
{x} as non
empty directed Subset of
S by WAYBEL_0:5;
A6:
(
ex_sup_of Y "/\" D,
S &
f preserves_sup_of {x} "/\" D )
by WAYBEL_0:75, WAYBEL_0:def 33;
A7:
{(f . x)} "/\" (f .: D) = { ((f . x) "/\" y) where y is Element of T : y in f .: D }
by YELLOW_4:42;
A8:
{x} "/\" D = { (x "/\" y) where y is Element of S : y in D }
by YELLOW_4:42;
A9:
{(f . x)} "/\" (f .: D) c= f .: ({x} "/\" D)
A13:
f .: ({x} "/\" D) c= {(f . x)} "/\" (f .: D)
reconsider X =
f .: D as
directed Subset of
T by Lm1, YELLOW_2:17;
f . (x "/\" (sup D)) =
(f . x) "/\" (f . (sup D))
by A2, Th1
.=
(f . x) "/\" (sup X)
by A5, WAYBEL_0:def 31
.=
sup ({(f . x)} "/\" X)
by A3, WAYBEL_2:def 6
.=
sup (f .: ({x} "/\" D))
by A9, A13, XBOOLE_0:def 10
.=
f . (sup ({x} "/\" D))
by A6, WAYBEL_0:def 31
;
hence
x "/\" (sup D) = sup ({x} "/\" D)
by A2, A4, FUNCT_1:def 8;
:: thesis: verum
end;
hence
S is meet-continuous
; :: thesis: verum