let N be complete meet-continuous Lawson TopLattice; :: thesis: for S being Scott TopAugmentation of N
for x being Point of S
for y being Point of N
for J being Basis of y st x = y holds
{ (uparrow A) where A is Subset of N : A in J } is Basis of x
let S be Scott TopAugmentation of N; :: thesis: for x being Point of S
for y being Point of N
for J being Basis of y st x = y holds
{ (uparrow A) where A is Subset of N : A in J } is Basis of x
let x be Point of S; :: thesis: for y being Point of N
for J being Basis of y st x = y holds
{ (uparrow A) where A is Subset of N : A in J } is Basis of x
let y be Point of N; :: thesis: for J being Basis of y st x = y holds
{ (uparrow A) where A is Subset of N : A in J } is Basis of x
let J be Basis of y; :: thesis: ( x = y implies { (uparrow A) where A is Subset of N : A in J } is Basis of x )
assume A1:
x = y
; :: thesis: { (uparrow A) where A is Subset of N : A in J } is Basis of x
A2:
RelStr(# the carrier of N,the InternalRel of N #) = RelStr(# the carrier of S,the InternalRel of S #)
by YELLOW_9:def 4;
set Z = { (uparrow A) where A is Subset of N : A in J } ;
set K = { (uparrow A) where A is Subset of N : A in J } ;
{ (uparrow A) where A is Subset of N : A in J } is Subset-Family of S
then reconsider K = { (uparrow A) where A is Subset of N : A in J } as Subset-Family of S ;
K is Basis of x
proof
thus
K c= the
topology of
S
:: according to YELLOW_8:def 2 :: thesis: ( x in Intersect K & ( for b1 being Element of bool the carrier of S holds
( not b1 is open or not x in b1 or ex b2 being Element of bool the carrier of S st
( b2 in K & b2 c= b1 ) ) ) )
for
k being
set st
k in K holds
x in k
hence
x in Intersect K
by SETFAM_1:58;
:: thesis: for b1 being Element of bool the carrier of S holds
( not b1 is open or not x in b1 or ex b2 being Element of bool the carrier of S st
( b2 in K & b2 c= b1 ) )
let sA be
Subset of
S;
:: thesis: ( not sA is open or not x in sA or ex b1 being Element of bool the carrier of S st
( b1 in K & b1 c= sA ) )
assume A9:
(
sA is
open &
x in sA )
;
:: thesis: ex b1 being Element of bool the carrier of S st
( b1 in K & b1 c= sA )
reconsider lA =
sA as
Subset of
N by A2;
sigma N c= lambda N
by Th10;
then A10:
sigma S c= lambda N
by A2, YELLOW_9:52;
N is
correct Lawson TopAugmentation of
S
by A2, YELLOW_9:def 4;
then
lA is
open
by A9, WAYBEL19:37;
then
lA in lambda N
by Th12;
then
uparrow lA in sigma S
by Th14;
then A11:
uparrow lA is
open
by A10, Th12;
lA c= uparrow lA
by WAYBEL_0:16;
then consider lV1 being
Subset of
N such that A12:
lV1 in J
and A13:
lV1 c= uparrow lA
by A1, A9, A11, YELLOW_8:def 2;
reconsider sUV =
uparrow lV1 as
Subset of
S by A2;
take
sUV
;
:: thesis: ( sUV in K & sUV c= sA )
thus
sUV in K
by A12;
:: thesis: sUV c= sA
A14:
sA = uparrow sA
A15:
uparrow sA = uparrow lA
by A2, WAYBEL_0:13;
lV1 is_coarser_than uparrow lA
by A13, WAYBEL12:20;
hence
sUV c= sA
by A14, A15, YELLOW12:28;
:: thesis: verum
end;
hence
{ (uparrow A) where A is Subset of N : A in J } is Basis of x
; :: thesis: verum