let L be non empty RelStr ; :: thesis: for S being Subset of L holds
( S is sups-closed iff for X being Subset of S st ex_sup_of X,L holds
"\/" X,L in S )
let S be Subset of L; :: thesis: ( S is sups-closed iff for X being Subset of S st ex_sup_of X,L holds
"\/" X,L in S )
thus
( S is sups-closed implies for X being Subset of S st ex_sup_of X,L holds
"\/" X,L in S )
:: thesis: ( ( for X being Subset of S st ex_sup_of X,L holds
"\/" X,L in S ) implies S is sups-closed )proof
assume
S is
sups-closed
;
:: thesis: for X being Subset of S st ex_sup_of X,L holds
"\/" X,L in S
then A1:
subrelstr S is
sups-inheriting
by Def4;
let X be
Subset of
S;
:: thesis: ( ex_sup_of X,L implies "\/" X,L in S )
A2:
X is
Subset of
(subrelstr S)
by YELLOW_0:def 15;
assume
ex_sup_of X,
L
;
:: thesis: "\/" X,L in S
then
"\/" X,
L in the
carrier of
(subrelstr S)
by A1, A2, YELLOW_0:def 19;
hence
"\/" X,
L in S
by YELLOW_0:def 15;
:: thesis: verum
end;
assume A3:
for X being Subset of S st ex_sup_of X,L holds
"\/" X,L in S
; :: thesis: S is sups-closed
then
subrelstr S is sups-inheriting
by YELLOW_0:def 19;
hence
S is sups-closed
by Def4; :: thesis: verum