let n, ni be non empty Element of NAT ; :: thesis: ( ni divides n implies ni -roots_of_1 c= n -roots_of_1 )
assume A1: ni divides n ; :: thesis: ni -roots_of_1 c= n -roots_of_1
consider k being Nat such that
A2: n = ni * k by A1, NAT_D:def 3;
reconsider k = k as Element of NAT by ORDINAL1:def 13;
for x being set st x in ni -roots_of_1 holds
x in n -roots_of_1
proof end;
hence ni -roots_of_1 c= n -roots_of_1 by TARSKI:def 3; :: thesis: verum