A2:
( dom (doms p) = dom p & doms p is Tree-yielding & Seg (len p) = dom p )
by A1, FINSEQ_1:def 3, TREES_3:39;
then reconsider q = doms p as Tree-yielding FinSequence by FINSEQ_1:def 2;
defpred S1[ set , set ] means ( ( $1 = {} & $2 = x ) or ( $1 <> {} & ex n being Element of NAT ex r being FinSequence st
( $1 = <*n*> ^ r & $2 = p .. (n + 1),r ) ) );
A3:
for y being set st y in tree q holds
ex z being set st S1[y,z]
consider T being Function such that
A5:
( dom T = tree q & ( for y being set st y in tree q holds
S1[y,T . y] ) )
from CLASSES1:sch 1(A3);
reconsider T = T as DecoratedTree by A5, TREES_2:def 8;
take
T
; :: thesis: ( ex q being DTree-yielding FinSequence st
( p = q & dom T = tree (doms q) ) & T . {} = x & ( for n being Element of NAT st n < len p holds
T | <*n*> = p . (n + 1) ) )
thus
ex q being DTree-yielding FinSequence st
( p = q & dom T = tree (doms q) )
by A1, A5; :: thesis: ( T . {} = x & ( for n being Element of NAT st n < len p holds
T | <*n*> = p . (n + 1) ) )
{} in tree q
by TREES_1:47;
hence
T . {} = x
by A5; :: thesis: for n being Element of NAT st n < len p holds
T | <*n*> = p . (n + 1)
A6:
len p = len q
by A2, FINSEQ_3:31;
let n be Element of NAT ; :: thesis: ( n < len p implies T | <*n*> = p . (n + 1) )
assume A7:
n < len p
; :: thesis: T | <*n*> = p . (n + 1)
then A8:
n + 1 in dom p
by Lm2;
then reconsider t = p . (n + 1) as DecoratedTree by A1, TREES_3:26;
A9:
( {} in dom t & dom t = q . (n + 1) & <*n*> ^ {} = <*n*> )
by A8, FINSEQ_1:47, FUNCT_6:31, TREES_1:47;
A10: dom t =
q . (n + 1)
by A8, FUNCT_6:31
.=
(dom T) | <*n*>
by A5, A6, A7, TREES_3:52
;
A11:
(dom T) | <*n*> = dom (T | <*n*>)
by TREES_2:def 11;
now let r be
FinSequence of
NAT ;
:: thesis: ( r in dom t implies (T | <*n*>) . r = t . r )assume A12:
r in dom t
;
:: thesis: (T | <*n*>) . r = t . rthen
(
<*n*> ^ r in dom T &
<*n*> ^ r <> {} )
by A5, A6, A7, A9, TREES_3:def 15;
then consider m being
Element of
NAT ,
s being
FinSequence such that A13:
(
<*n*> ^ r = <*m*> ^ s &
T . (<*n*> ^ r) = p .. (m + 1),
s )
by A5;
(
(<*n*> ^ r) . 1
= n &
(<*m*> ^ s) . 1
= m )
by FINSEQ_1:58;
then
(
m + 1
in dom p &
n = m &
r = s )
by A7, A13, Lm2, FINSEQ_1:46;
then
p .. (m + 1),
s = t . r
by A12, FUNCT_5:45;
hence
(T | <*n*>) . r = t . r
by A10, A12, A13, TREES_2:def 11;
:: thesis: verum end;
hence
T | <*n*> = p . (n + 1)
by A10, A11, TREES_2:33; :: thesis: verum