let T1, T2 be Tree; :: thesis: for p being Element of T1 \/ T2 holds ( ( p in T1 & p in T2 implies (T1 \/ T2)| p =(T1 | p)\/(T2 | p) ) & ( not p in T1 implies (T1 \/ T2)| p = T2 | p ) & ( not p in T2 implies (T1 \/ T2)| p = T1 | p ) ) let p be Element of T1 \/ T2; :: thesis: ( ( p in T1 & p in T2 implies (T1 \/ T2)| p =(T1 | p)\/(T2 | p) ) & ( not p in T1 implies (T1 \/ T2)| p = T2 | p ) & ( not p in T2 implies (T1 \/ T2)| p = T1 | p ) ) thus
( p in T1 & p in T2 implies (T1 \/ T2)| p =(T1 | p)\/(T2 | p) )
:: thesis: ( ( not p in T1 implies (T1 \/ T2)| p = T2 | p ) & ( not p in T2 implies (T1 \/ T2)| p = T1 | p ) )