then reconsider f = f as Complex_Sequenceby A6, COMSEQ_1:1; take seq = f; :: thesis: for n being Element of NAT holds ( ( n <= k implies seq . n = F1(k,n) ) & ( n > k implies seq . n =0 ) ) let n be Element of NAT ; :: thesis: ( ( n <= k implies seq . n = F1(k,n) ) & ( n > k implies seq . n =0 ) )
ex l being Element of NAT st ( l = n & ( l <= k implies seq . n = F1(k,l) ) & ( l > k implies seq . n =0c ) )
by A7; hence
( ( n <= k implies seq . n = F1(k,n) ) & ( n > k implies seq . n =0 ) )
; :: thesis: verum