let th1, th2 be real number ; :: thesis: ( th1 in ].0 ,1.[ & th2 in ].0 ,1.[ & tan . th1 = tan . th2 implies th1 = th2 )
assume A1:
( th1 in ].0 ,1.[ & th2 in ].0 ,1.[ & tan . th1 = tan . th2 )
; :: thesis: th1 = th2
then A2:
( 0 < th1 & th1 < 1 & 0 < th2 & th2 < 1 )
by XXREAL_1:4;
assume A3:
th1 <> th2
; :: thesis: contradiction
ex th being real number st
( th in ].0 ,1.[ & diff tan ,th = 0 )
proof
now per cases
( th1 < th2 or th2 < th1 )
by A3, XXREAL_0:1;
suppose A4:
th1 < th2
;
:: thesis: ex th being Real st
( th in ].0 ,1.[ & diff tan ,th = 0 )A5:
(
].th1,th2.[ is
open Subset of
REAL &
].th1,th2.[ c= ].0 ,1.[ &
[.th1,th2.] c= [.0 ,1.] )
proof
A6:
for
th being
Real st
th in ].th1,th2.[ holds
th in ].0 ,1.[
for
th being
Real st
th in [.th1,th2.] holds
th in [.0 ,1.]
hence
(
].th1,th2.[ is
open Subset of
REAL &
].th1,th2.[ c= ].0 ,1.[ &
[.th1,th2.] c= [.0 ,1.] )
by A6, SUBSET_1:7;
:: thesis: verum
end; then A9:
tan is_differentiable_on ].th1,th2.[
by Lm20, FDIFF_1:34;
tan | [.th1,th2.] is
continuous
by A5, Th76, FCONT_1:17;
then consider r being
Real such that A10:
(
r in ].th1,th2.[ &
diff tan ,
r = 0 )
by A1, A4, A9, A5, Th75, ROLLE:1, XBOOLE_1:1;
take th =
r;
:: thesis: ( th in ].0 ,1.[ & diff tan ,th = 0 )thus
(
th in ].0 ,1.[ &
diff tan ,
th = 0 )
by A5, A10;
:: thesis: verum end; suppose A11:
th2 < th1
;
:: thesis: ex th being Real st
( th in ].0 ,1.[ & diff tan ,th = 0 )A12:
(
].th2,th1.[ is
open Subset of
REAL &
].th2,th1.[ c= ].0 ,1.[ &
[.th2,th1.] c= [.0 ,1.] )
proof
A13:
for
th being
Real st
th in ].th2,th1.[ holds
th in ].0 ,1.[
for
th being
Real st
th in [.th2,th1.] holds
th in [.0 ,1.]
hence
(
].th2,th1.[ is
open Subset of
REAL &
].th2,th1.[ c= ].0 ,1.[ &
[.th2,th1.] c= [.0 ,1.] )
by A13, SUBSET_1:7;
:: thesis: verum
end; then A16:
tan is_differentiable_on ].th2,th1.[
by Lm20, FDIFF_1:34;
tan | [.th2,th1.] is
continuous
by A12, Th76, FCONT_1:17;
then consider r being
Real such that A17:
(
r in ].th2,th1.[ &
diff tan ,
r = 0 )
by A1, A11, A16, A12, Th75, ROLLE:1, XBOOLE_1:1;
take th =
r;
:: thesis: ( th in ].0 ,1.[ & diff tan ,th = 0 )thus
(
th in ].0 ,1.[ &
diff tan ,
th = 0 )
by A12, A17;
:: thesis: verum end; end; end;
hence
ex
th being
real number st
(
th in ].0 ,1.[ &
diff tan ,
th = 0 )
;
:: thesis: verum
end;
hence
contradiction
by Lm20; :: thesis: verum