let D be non empty set ; :: thesis: for e being Element of D
for F being BinOp of D
for p, q being FinSequence of D st len p = len q & F . e,e = e holds
F .: ([#] p,e),([#] q,e) = [#] (F .: p,q),e
let e be Element of D; :: thesis: for F being BinOp of D
for p, q being FinSequence of D st len p = len q & F . e,e = e holds
F .: ([#] p,e),([#] q,e) = [#] (F .: p,q),e
let F be BinOp of D; :: thesis: for p, q being FinSequence of D st len p = len q & F . e,e = e holds
F .: ([#] p,e),([#] q,e) = [#] (F .: p,q),e
let p, q be FinSequence of D; :: thesis: ( len p = len q & F . e,e = e implies F .: ([#] p,e),([#] q,e) = [#] (F .: p,q),e )
assume that
A1:
len p = len q
and
A2:
F . e,e = e
; :: thesis: F .: ([#] p,e),([#] q,e) = [#] (F .: p,q),e
set r = F .: p,q;
A3:
len (F .: p,q) = len p
by A1, FINSEQ_2:86;
A4:
( dom p = Seg (len p) & dom (F .: p,q) = Seg (len (F .: p,q)) & dom q = Seg (len q) )
by FINSEQ_1:def 3;
now let i be
Element of
NAT ;
:: thesis: (F .: ([#] p,e),([#] q,e)) . i = ([#] (F .: p,q),e) . inow per cases
( i in dom p or not i in dom p )
;
suppose A5:
i in dom p
;
:: thesis: F . (([#] p,e) . i),(([#] q,e) . i) = ([#] (F .: p,q),e) . ihence F . (([#] p,e) . i),
(([#] q,e) . i) =
F . (p . i),
(([#] q,e) . i)
by Th22
.=
F . (p . i),
(q . i)
by A1, A4, A5, Th22
.=
(F .: p,q) . i
by A3, A4, A5, FUNCOP_1:28
.=
([#] (F .: p,q),e) . i
by A3, A4, A5, Th22
;
:: thesis: verum end; suppose A6:
not
i in dom p
;
:: thesis: F . (([#] p,e) . i),(([#] q,e) . i) = ([#] (F .: p,q),e) . ihence F . (([#] p,e) . i),
(([#] q,e) . i) =
F . e,
(([#] q,e) . i)
by Th22
.=
e
by A1, A2, A4, A6, Th22
.=
([#] (F .: p,q),e) . i
by A3, A4, A6, Th22
;
:: thesis: verum end; end; end; hence
(F .: ([#] p,e),([#] q,e)) . i = ([#] (F .: p,q),e) . i
by FUNCOP_1:48;
:: thesis: verum end;
hence
F .: ([#] p,e),([#] q,e) = [#] (F .: p,q),e
by FUNCT_2:113; :: thesis: verum