let r be real number ; :: thesis: for seq being Real_Sequence st 0 <= r & ( for n being Element of NAT holds seq . n = 1 / ((n * n) + r) ) holds
lim seq = 0
let seq be Real_Sequence; :: thesis: ( 0 <= r & ( for n being Element of NAT holds seq . n = 1 / ((n * n) + r) ) implies lim seq = 0 )
assume that
A1:
0 <= r
and
A2:
for n being Element of NAT holds seq . n = 1 / ((n * n) + r)
; :: thesis: lim seq = 0
A3:
seq is convergent
by A1, A2, Th47;
now let p be
real number ;
:: thesis: ( 0 < p implies ex n being Element of NAT st
for m being Element of NAT st n <= m holds
abs ((seq . m) - 0 ) < p )assume A4:
0 < p
;
:: thesis: ex n being Element of NAT st
for m being Element of NAT st n <= m holds
abs ((seq . m) - 0 ) < pthen A5:
0 < p "
;
consider k1 being
Element of
NAT such that A6:
p " < k1
by Th10;
take n =
k1;
:: thesis: for m being Element of NAT st n <= m holds
abs ((seq . m) - 0 ) < plet m be
Element of
NAT ;
:: thesis: ( n <= m implies abs ((seq . m) - 0 ) < p )assume A7:
n <= m
;
:: thesis: abs ((seq . m) - 0 ) < p
(
0 <= n &
0 <= m )
by NAT_1:2;
then A8:
n * n <= m * m
by A7, XREAL_1:68;
A9:
k1 > 0
by A4, A6;
then
k1 >= 1
+ 0
by NAT_1:13;
then
k1 <= k1 * k1
by XREAL_1:153;
then A10:
k1 + r <= (k1 * k1) + r
by XREAL_1:8;
(p " ) + 0 < k1 + r
by A1, A6, XREAL_1:10;
then
(p " ) + 0 < (k1 * k1) + r
by A10, XXREAL_0:2;
then
1
/ ((k1 * k1) + r) < 1
/ (p " )
by A5, XREAL_1:78;
then A11:
1
/ ((k1 * k1) + r) < 1
* ((p " ) " )
by XCMPLX_0:def 9;
B12:
0 < n ^2
by A9, SQUARE_1:74;
(n * n) + r <= (m * m) + r
by A8, XREAL_1:8;
then
1
/ ((m * m) + r) <= 1
/ ((n * n) + r)
by A1, B12, XREAL_1:120;
then A13:
1
/ ((m * m) + r) < p
by A11, XXREAL_0:2;
A14:
seq . m = 1
/ ((m * m) + r)
by A2;
0 <= m * m
by NAT_1:2;
hence
abs ((seq . m) - 0 ) < p
by A13, A14, A1, ABSVALUE:def 1;
:: thesis: verum end;
hence
lim seq = 0
by A3, SEQ_2:def 7; :: thesis: verum