let x, y be Element of B_6 ; :: thesis: ( x = 3 \ 2 & y = 2 implies ( x "\/" y = 3 & x "/\" y = 0 ) )
Z1:
the carrier of B_6 = {0 ,1,(3 \ 1),2,(3 \ 2),3}
by YELLOW_1:1;
assume Z:
( x = 3 \ 2 & y = 2 )
; :: thesis: ( x "\/" y = 3 & x "/\" y = 0 )
x misses y
by Z, XBOOLE_1:79;
then P:
x /\ y = 0
by XBOOLE_0:def 7;
B:
2 c= 3
by NAT_1:40;
C: 2 \/ (3 \ 2) =
2 \/ 3
by XBOOLE_1:39
.=
3
by B, XBOOLE_1:12
;
reconsider z = 3 as Element of B_6 by Z1, ENUMSET1:def 4;
hence
x "\/" y = 3
by YELLOW_0:22; :: thesis: x "/\" y = 0
reconsider z = 0 as Element of B_6 by Z1, ENUMSET1:def 4;
hence
x "/\" y = 0
by YELLOW_0:23; :: thesis: verum