let D1 be non empty set ; :: thesis: for f being FinSequence of PFuncs D1,REAL
for d being Element of D1
for n being Element of NAT holds (f | n) # d = (f # d) | n
let f be FinSequence of PFuncs D1,REAL ; :: thesis: for d being Element of D1
for n being Element of NAT holds (f | n) # d = (f # d) | n
let d1 be Element of D1; :: thesis: for n being Element of NAT holds (f | n) # d1 = (f # d1) | n
let n be Element of NAT ; :: thesis: (f | n) # d1 = (f # d1) | n
A1:
( len (f # d1) = len f & len ((f | n) # d1) = len (f | n) )
by Def8;
now per cases
( len f <= n or n < len f )
;
case A3:
n < len f
;
:: thesis: (f | n) # d1 = (f # d1) | nthen A4:
(
len (f | n) = n &
len ((f # d1) | n) = n )
by A1, FINSEQ_1:80;
A5:
(
dom f = Seg (len f) &
dom (f # d1) = Seg (len (f # d1)) &
dom ((f | n) # d1) = Seg (len ((f | n) # d1)) )
by FINSEQ_1:def 3;
now per cases
( n = 0 or n <> 0 )
;
case
n <> 0
;
:: thesis: (f | n) # d1 = (f # d1) | nthen
0 < n
;
then
0 + 1
<= n
by NAT_1:13;
then A6:
n in dom f
by A3, FINSEQ_3:27;
X:
dom ((f # d1) | n) = Seg (len (f | n))
by A4, FINSEQ_1:def 3;
now let m be
Nat;
:: thesis: ( m in dom ((f # d1) | n) implies ((f # d1) | n) . m = ((f | n) # d1) . m )assume A7:
m in dom ((f # d1) | n)
;
:: thesis: ((f # d1) | n) . m = ((f | n) # d1) . mthen A8:
(
((f # d1) | n) . m = (f # d1) . m &
m in dom (f # d1) )
by A1, A4, A5, A6, X, RFINSEQ:19;
then reconsider G =
f . m as
Element of
PFuncs D1,
REAL by A1, A5, FINSEQ_2:13;
A9:
((f # d1) | n) . m = G . d1
by A8, Def8;
(
(f | n) . m = G &
m in dom f )
by A4, A6, A7, X, RFINSEQ:19;
hence
((f # d1) | n) . m = ((f | n) # d1) . m
by A1, A5, A7, A9, Def8, X;
:: thesis: verum end; hence
(f | n) # d1 = (f # d1) | n
by A1, A4, FINSEQ_2:10;
:: thesis: verum end; end; end; hence
(f | n) # d1 = (f # d1) | n
;
:: thesis: verum end; end; end;
hence
(f | n) # d1 = (f # d1) | n
; :: thesis: verum