let X, Y be set ; :: thesis: for C being non empty set holds (chi X,C) (#) (chi Y,C) = chi (X /\ Y),C
let C be non empty set ; :: thesis: (chi X,C) (#) (chi Y,C) = chi (X /\ Y),C
A1: dom ((chi X,C) (#) (chi Y,C)) =
(dom (chi X,C)) /\ (dom (chi Y,C))
by VALUED_1:def 4
.=
C /\ (dom (chi Y,C))
by Th77
.=
C /\ C
by Th77
.=
dom (chi (X /\ Y),C)
by Th77
;
now let c be
Element of
C;
:: thesis: ( c in dom ((chi X,C) (#) (chi Y,C)) implies ((chi X,C) (#) (chi Y,C)) . c = (chi (X /\ Y),C) . c )assume
c in dom ((chi X,C) (#) (chi Y,C))
;
:: thesis: ((chi X,C) (#) (chi Y,C)) . c = (chi (X /\ Y),C) . chence
((chi X,C) (#) (chi Y,C)) . c = (chi (X /\ Y),C) . c
by VALUED_1:5;
:: thesis: verum end;
hence
(chi X,C) (#) (chi Y,C) = chi (X /\ Y),C
by A1, PARTFUN1:34; :: thesis: verum