let X, Y be set ; :: thesis: for R being Relation holds (X /\ Y) | R = (X | R) /\ (Y | R)
let R be Relation; :: thesis: (X /\ Y) | R = (X | R) /\ (Y | R)
for x, y being set holds
( [x,y] in (X /\ Y) | R iff [x,y] in (X | R) /\ (Y | R) )
proof
let x,
y be
set ;
:: thesis: ( [x,y] in (X /\ Y) | R iff [x,y] in (X | R) /\ (Y | R) )
( (
[x,y] in (X /\ Y) | R implies (
y in X /\ Y &
[x,y] in R ) ) & (
y in X /\ Y &
[x,y] in R implies
[x,y] in (X /\ Y) | R ) & (
y in X /\ Y implies (
y in X &
y in Y ) ) & (
y in X &
y in Y implies
y in X /\ Y ) & (
[x,y] in (X | R) /\ (Y | R) implies (
[x,y] in X | R &
[x,y] in Y | R ) ) & (
[x,y] in X | R &
[x,y] in Y | R implies
[x,y] in (X | R) /\ (Y | R) ) & (
[x,y] in X | R implies (
y in X &
[x,y] in R ) ) & (
y in X &
[x,y] in R implies
[x,y] in X | R ) & (
[x,y] in Y | R implies (
y in Y &
[x,y] in R ) ) & (
y in Y &
[x,y] in R implies
[x,y] in Y | R ) )
by Def12, XBOOLE_0:def 4;
hence
(
[x,y] in (X /\ Y) | R iff
[x,y] in (X | R) /\ (Y | R) )
;
:: thesis: verum
end;
hence
(X /\ Y) | R = (X | R) /\ (Y | R)
by Def2; :: thesis: verum