set S = SgmX (RelIncl n),(support b);
set l = len (SgmX (RelIncl n),(support b));
defpred S1[ Element of NAT , Element of L] means $2 = (power L) . ((x * (SgmX (RelIncl n),(support b))) /. $1),((b * (SgmX (RelIncl n),(support b))) /. $1);
A1:
for k being Element of NAT st k in Seg (len (SgmX (RelIncl n),(support b))) holds
ex x being Element of L st S1[k,x]
;
consider p being FinSequence of the carrier of L such that
A2:
( dom p = Seg (len (SgmX (RelIncl n),(support b))) & ( for k being Element of NAT st k in Seg (len (SgmX (RelIncl n),(support b))) holds
S1[k,p /. k] ) )
from POLYNOM2:sch 1(A1);
take
Product p
; :: thesis: ex y being FinSequence of the carrier of L st
( len y = len (SgmX (RelIncl n),(support b)) & Product p = Product y & ( for i being Element of NAT st 1 <= i & i <= len y holds
y /. i = (power L) . ((x * (SgmX (RelIncl n),(support b))) /. i),((b * (SgmX (RelIncl n),(support b))) /. i) ) )
A3:
len p = len (SgmX (RelIncl n),(support b))
by A2, FINSEQ_1:def 3;
now let m be
Element of
NAT ;
:: thesis: ( 1 <= m & m <= len p implies p /. m = (power L) . ((x * (SgmX (RelIncl n),(support b))) /. m),((b * (SgmX (RelIncl n),(support b))) /. m) )assume
( 1
<= m &
m <= len p )
;
:: thesis: p /. m = (power L) . ((x * (SgmX (RelIncl n),(support b))) /. m),((b * (SgmX (RelIncl n),(support b))) /. m)then
m in Seg (len (SgmX (RelIncl n),(support b)))
by A3, FINSEQ_1:3;
hence
p /. m = (power L) . ((x * (SgmX (RelIncl n),(support b))) /. m),
((b * (SgmX (RelIncl n),(support b))) /. m)
by A2;
:: thesis: verum end;
hence
ex y being FinSequence of the carrier of L st
( len y = len (SgmX (RelIncl n),(support b)) & Product p = Product y & ( for i being Element of NAT st 1 <= i & i <= len y holds
y /. i = (power L) . ((x * (SgmX (RelIncl n),(support b))) /. i),((b * (SgmX (RelIncl n),(support b))) /. i) ) )
by A3; :: thesis: verum