let P, Q be pcs; :: thesis: ( P misses Q implies pcs-sum P,Q is pcs )
assume A1:
P misses Q
; :: thesis: pcs-sum P,Q is pcs
set R = pcs-sum P,Q;
pcs-sum P,Q is pcs-like
proof
A2:
field the
InternalRel of
(pcs-sum P,Q) = the
carrier of
(pcs-sum P,Q)
by ORDERS_1:97;
thus
pcs-sum P,
Q is
reflexive
;
:: according to PCS_0:def 23 :: thesis: ( pcs-sum P,Q is transitive & pcs-sum P,Q is pcs-tol-reflexive & pcs-sum P,Q is pcs-tol-symmetric & pcs-sum P,Q is pcs-compatible )
thus
pcs-sum P,
Q is
transitive
:: thesis: ( pcs-sum P,Q is pcs-tol-reflexive & pcs-sum P,Q is pcs-tol-symmetric & pcs-sum P,Q is pcs-compatible )
thus
(
pcs-sum P,
Q is
pcs-tol-reflexive &
pcs-sum P,
Q is
pcs-tol-symmetric )
;
:: thesis: pcs-sum P,Q is pcs-compatible
thus
pcs-sum P,
Q is
pcs-compatible
by A1, Th19;
:: thesis: verum
end;
hence
pcs-sum P,Q is pcs
; :: thesis: verum