let OAS be OAffinSpace; :: thesis: for a, b, d, x, c being Element of OAS st Mid a,b,d & Mid b,x,c & not LIN a,b,c holds
ex y being Element of OAS st
( Mid a,y,c & Mid y,x,d )
let a, b, d, x, c be Element of OAS; :: thesis: ( Mid a,b,d & Mid b,x,c & not LIN a,b,c implies ex y being Element of OAS st
( Mid a,y,c & Mid y,x,d ) )
assume A1:
( Mid a,b,d & Mid b,x,c & not LIN a,b,c )
; :: thesis: ex y being Element of OAS st
( Mid a,y,c & Mid y,x,d )
then A2:
( Mid d,b,a & Mid c,x,b )
by DIRAF:13;
A3:
now assume A4:
(
b <> d &
x <> b )
;
:: thesis: ex y being Element of OAS st
( Mid a,y,c & Mid y,x,d )
d,
b // b,
a
by A2, DIRAF:def 3;
then consider e1 being
Element of
OAS such that A5:
(
x,
b // b,
e1 &
x,
d // a,
e1 )
by A4, ANALOAF:def 5;
A6:
Mid x,
b,
e1
by A5, DIRAF:def 3;
then A7:
Mid e1,
b,
x
by DIRAF:13;
then A8:
Mid e1,
x,
c
by A1, A4, DIRAF:16;
then A9:
Mid c,
x,
e1
by DIRAF:13;
A10:
c <> e1
A11:
x <> e1
by A4, A6, DIRAF:12;
A12:
not
LIN c,
a,
e1
proof
assume
LIN c,
a,
e1
;
:: thesis: contradiction
then A13:
LIN c,
e1,
a
by DIRAF:36;
LIN c,
x,
e1
by A8, DIRAF:13, DIRAF:34;
then
(
LIN c,
e1,
x &
LIN x,
b,
e1 )
by A6, DIRAF:34, DIRAF:36;
then
(
LIN c,
e1,
x &
LIN c,
e1,
e1 &
LIN x,
e1,
b )
by DIRAF:36, DIRAF:37;
then
(
LIN c,
e1,
b &
LIN c,
e1,
c )
by A11, DIRAF:37, DIRAF:41;
hence
contradiction
by A1, A10, A13, DIRAF:38;
:: thesis: verum
end; then consider y being
Element of
OAS such that A14:
(
Mid c,
y,
a &
a,
e1 // y,
x )
by A9, Th28;
a <> e1
by A12, DIRAF:37;
then
x,
d // y,
x
by A5, A14, DIRAF:6;
then
d,
x // x,
y
by DIRAF:5;
then
Mid d,
x,
y
by DIRAF:def 3;
then
(
Mid a,
y,
c &
Mid y,
x,
d )
by A14, DIRAF:13;
hence
ex
y being
Element of
OAS st
(
Mid a,
y,
c &
Mid y,
x,
d )
;
:: thesis: verum end;
A15:
now assume A16:
(
b <> d &
x = b )
;
:: thesis: ex y being Element of OAS st
( Mid a,y,c & Mid y,x,d )take y =
a;
:: thesis: ( Mid a,y,c & Mid y,x,d )thus
(
Mid a,
y,
c &
Mid y,
x,
d )
by A1, A16, DIRAF:14;
:: thesis: verum end;
now assume A17:
b = d
;
:: thesis: ex y being Element of OAS st
( Mid a,y,c & Mid d,x,y & Mid a,y,c & Mid y,x,d )take y =
c;
:: thesis: ( Mid a,y,c & Mid d,x,y & Mid a,y,c & Mid y,x,d )thus
(
Mid a,
y,
c &
Mid d,
x,
y )
by A1, A17, DIRAF:14;
:: thesis: ( Mid a,y,c & Mid y,x,d )thus
(
Mid a,
y,
c &
Mid y,
x,
d )
by A1, A17, DIRAF:13, DIRAF:14;
:: thesis: verum end;
hence
ex y being Element of OAS st
( Mid a,y,c & Mid y,x,d )
by A3, A15; :: thesis: verum