let OAS be OAffinSpace; :: thesis: for p, b, c, a, d being Element of OAS st Mid p,b,c & LIN p,a,d & a,b '||' c,d & not LIN p,a,b holds
Mid p,a,d
let p, b, c, a, d be Element of OAS; :: thesis: ( Mid p,b,c & LIN p,a,d & a,b '||' c,d & not LIN p,a,b implies Mid p,a,d )
assume that
A1:
Mid p,b,c
and
A2:
LIN p,a,d
and
A3:
a,b '||' c,d
and
A4:
not LIN p,a,b
; :: thesis: Mid p,a,d
A5:
now assume
b = c
;
:: thesis: Mid p,a,dthen
(
LIN p,
b,
b &
LIN p,
a,
a &
a,
b '||' b,
a &
a,
b '||' b,
d )
by A3, DIRAF:24, DIRAF:37;
then
a = d
by A2, A4, Th11;
hence
Mid p,
a,
d
by DIRAF:14;
:: thesis: verum end;
now assume A6:
b <> c
;
:: thesis: Mid p,a,dthen A7:
p <> c
by A1, DIRAF:12;
A8:
b <> a
by A4, DIRAF:37;
A9:
not
LIN d,
b,
a
proof
assume
LIN d,
b,
a
;
:: thesis: contradiction
then
(
LIN a,
b,
d &
a,
b '||' d,
c )
by A3, DIRAF:27, DIRAF:36;
then
LIN a,
b,
c
by A8, DIRAF:39;
then A10:
LIN b,
c,
a
by DIRAF:36;
LIN p,
b,
c
by A1, DIRAF:34;
then
(
LIN b,
c,
p &
LIN b,
c,
b )
by DIRAF:36, DIRAF:37;
hence
contradiction
by A4, A6, A10, DIRAF:38;
:: thesis: verum
end; then A11:
d <> a
by DIRAF:37;
LIN d,
a,
p
by A2, DIRAF:36;
then
d,
a '||' d,
p
by DIRAF:def 5;
then
a,
d '||' d,
p
by DIRAF:27;
then consider q being
Element of
OAS such that A12:
b,
d '||' d,
q
and A13:
b,
a '||' p,
q
by A11, DIRAF:32;
A14:
not
LIN b,
c,
d
proof
assume A15:
LIN b,
c,
d
;
:: thesis: contradiction
then A16:
(
LIN b,
c,
d &
LIN b,
c,
b )
by DIRAF:37;
LIN c,
d,
b
by A15, DIRAF:36;
then A17:
c,
d '||' c,
b
by DIRAF:def 5;
then
(
LIN p,
a,
c &
LIN p,
b,
c )
by A1, A2, A3, A17, DIRAF:28, DIRAF:34;
then
(
LIN p,
c,
b &
LIN p,
c,
c &
LIN p,
c,
a )
by DIRAF:36, DIRAF:37;
then
LIN b,
c,
a
by A7, DIRAF:38;
hence
contradiction
by A6, A9, A16, DIRAF:38;
:: thesis: verum
end; A18:
Mid d,
b,
q
proof
d,
b '||' d,
q
by A12, DIRAF:27;
then
LIN d,
b,
q
by DIRAF:def 5;
then A19:
LIN b,
d,
q
by DIRAF:36;
a,
b '||' q,
p
by A13, DIRAF:27;
then A20:
c,
d '||' q,
p
by A3, A8, DIRAF:28;
Mid c,
b,
p
by A1, DIRAF:13;
hence
Mid d,
b,
q
by A14, A19, A20, Th13;
:: thesis: verum
end; assume A21:
not
Mid p,
a,
d
;
:: thesis: contradictionA22:
d <> p
proof
assume
d = p
;
:: thesis: contradiction
then
(
LIN p,
b,
c &
p,
c '||' b,
a )
by A1, A3, DIRAF:27, DIRAF:34;
then
(
LIN p,
c,
b &
p,
c '||' b,
a )
by DIRAF:36;
then
(
LIN p,
c,
p &
LIN p,
c,
a &
LIN p,
c,
b )
by A7, DIRAF:37, DIRAF:39;
hence
contradiction
by A4, A7, DIRAF:38;
:: thesis: verum
end; A23:
not
LIN d,
p,
q
proof
assume
LIN d,
p,
q
;
:: thesis: contradiction
then
(
LIN d,
p,
p &
LIN d,
p,
q &
LIN d,
p,
a )
by A2, DIRAF:36, DIRAF:37;
then A24:
LIN p,
q,
a
by A22, DIRAF:38;
A25:
p,
q '||' a,
b
by A13, DIRAF:27;
now assume
p = q
;
:: thesis: contradictionthen
d,
b '||' d,
p
by A12, DIRAF:27;
then
LIN d,
b,
p
by DIRAF:def 5;
then
(
LIN d,
p,
d &
LIN d,
p,
b &
LIN d,
p,
a )
by A2, DIRAF:36, DIRAF:37;
hence
contradiction
by A9, A22, DIRAF:38;
:: thesis: verum end;
then
(
p <> q &
LIN p,
q,
p &
LIN p,
q,
a &
LIN p,
q,
b )
by A24, A25, DIRAF:37, DIRAF:39;
hence
contradiction
by A4, DIRAF:38;
:: thesis: verum
end; now assume
Mid p,
d,
a
;
:: thesis: contradictionthen
(
Mid p,
d,
a &
d,
b '||' d,
q )
by A12, DIRAF:27;
then
(
Mid p,
d,
a &
LIN d,
b,
q )
by DIRAF:def 5;
then
(
Mid p,
d,
a &
LIN d,
q,
b &
p,
q '||' b,
a )
by A13, DIRAF:27, DIRAF:36;
then
Mid q,
d,
b
by A23, Th13;
then
Mid b,
d,
q
by DIRAF:13;
then
b = d
by A18, DIRAF:18;
hence
contradiction
by A9, DIRAF:37;
:: thesis: verum end; then
(
Mid a,
p,
d &
LIN p,
b,
c )
by A1, A2, A21, DIRAF:34, DIRAF:35;
then
Mid b,
p,
c
by A3, A4, Th13;
then
p = b
by A1, DIRAF:18;
hence
contradiction
by A4, DIRAF:37;
:: thesis: verum end;
hence
Mid p,a,d
by A5; :: thesis: verum