let OAS be OAffinSpace; :: thesis: for p, a, b, c, d1, d2 being Element of OAS st not LIN p,a,b & LIN p,b,c & LIN p,a,d1 & LIN p,a,d2 & a,b '||' c,d1 & a,b '||' c,d2 holds
d1 = d2
let p, a, b, c, d1, d2 be Element of OAS; :: thesis: ( not LIN p,a,b & LIN p,b,c & LIN p,a,d1 & LIN p,a,d2 & a,b '||' c,d1 & a,b '||' c,d2 implies d1 = d2 )
assume that
A1:
not LIN p,a,b
and
A2:
LIN p,b,c
and
A3:
LIN p,a,d1
and
A4:
LIN p,a,d2
and
A5:
a,b '||' c,d1
and
A6:
a,b '||' c,d2
; :: thesis: d1 = d2
A7:
( LIN p,d1,a & LIN p,d2,a )
by A3, A4, DIRAF:36;
A8:
( p <> a & p <> b & a <> b )
by A1, DIRAF:37;
A9:
now assume
c = p
;
:: thesis: d1 = d2then A10:
(
p,
d1 '||' a,
b &
p,
d2 '||' a,
b )
by A5, A6, DIRAF:27;
A11:
(
LIN p,
d1,
p &
LIN p,
d2,
p )
by DIRAF:37;
hence
d1 = d2
by A12;
:: thesis: verum end;
now assume A15:
p <> c
;
:: thesis: not d1 <> d2assume A16:
d1 <> d2
;
:: thesis: contradictionA17:
LIN p,
a,
p
by DIRAF:37;
then A18:
LIN d1,
d2,
p
by A3, A4, A8, DIRAF:38;
LIN p,
a,
a
by DIRAF:37;
then A19:
LIN d1,
d2,
a
by A3, A4, A8, DIRAF:38;
c,
d1 '||' c,
d2
by A5, A6, A8, DIRAF:28;
then A20:
LIN c,
d1,
d2
by DIRAF:def 5;
then A21:
LIN d1,
d2,
c
by DIRAF:36;
(
LIN d1,
d2,
p &
LIN d1,
d2,
c &
LIN d1,
d2,
d1 )
by A3, A4, A8, A17, A20, DIRAF:36, DIRAF:38;
then A22:
LIN p,
c,
d1
by A16, DIRAF:38;
LIN d1,
d2,
d2
by DIRAF:37;
then
(
LIN p,
c,
d2 &
LIN p,
c,
b )
by A2, A16, A18, A21, DIRAF:36, DIRAF:38;
then
LIN d1,
d2,
b
by A15, A22, DIRAF:38;
hence
contradiction
by A1, A16, A18, A19, DIRAF:38;
:: thesis: verum end;
hence
d1 = d2
by A9; :: thesis: verum