let I be set ; :: thesis: for f, g being Function of I,NAT
for J, K being finite Subset of I holds Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))
let f, g be Function of I,NAT ; :: thesis: for J, K being finite Subset of I holds Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))
let J, K be finite Subset of I; :: thesis: Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))
defpred S1[ Nat] means for I being set
for f, g being Function of I,NAT
for J, K being finite Subset of I st $1 = card J holds
Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K));
A1:
for k being Nat st ( for n being Nat st n < k holds
S1[n] ) holds
S1[k]
proof
let k be
Nat;
:: thesis: ( ( for n being Nat st n < k holds
S1[n] ) implies S1[k] )
assume A2:
for
n being
Nat st
n < k holds
S1[
n]
;
:: thesis: S1[k]
thus
S1[
k]
:: thesis: verumproof
let I be
set ;
:: thesis: for f, g being Function of I,NAT
for J, K being finite Subset of I st k = card J holds
Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))let f,
g be
Function of
I,
NAT ;
:: thesis: for J, K being finite Subset of I st k = card J holds
Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))let J,
K be
finite Subset of
I;
:: thesis: ( k = card J implies Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K)) )
assume A3:
k = card J
;
:: thesis: Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))
(
k = 0 or
k + 1
> 0 + 1 )
by XREAL_1:10;
then A4:
(
k = 0 or
k >= 1 )
by NAT_1:13;
per cases
( k = 0 or k = 1 or k > 1 )
by A4, XXREAL_0:1;
suppose A5:
k = 0
;
:: thesis: Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))A6:
J = {}
by A3, A5;
A7:
[:J,K:] = {}
by A6;
set b =
EmptyBag {} ;
A8:
EmptyBag {} =
{} --> 0
by POLYNOM1:def 15
.=
{}
;
Sum (f | J) = 0
by A8, A6, RELAT_1:110, UPROOTS:13;
hence
Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))
by A8, A7, UPROOTS:13, RELAT_1:110;
:: thesis: verum end; suppose A11:
k > 1
;
:: thesis: Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))then
J <> {}
by A3;
then consider j being
set such that A12:
j in J
by XBOOLE_0:def 1;
set J0 =
{j};
set J1 =
J \ {j};
reconsider J0 =
{j} as
finite Subset of
I by A12, ZFMISC_1:37;
j in J0
by TARSKI:def 1;
then
not
j in J \ {j}
by XBOOLE_0:def 5;
then A13:
card ((J \ {j}) \/ J0) = (card (J \ {j})) + 1
by CARD_2:54;
A14:
(- 1) + k < 0 + k
by XREAL_1:10;
A15:
(J \ {j}) \/ J0 =
J \/ {j}
by XBOOLE_1:39
.=
J
by A12, ZFMISC_1:46
;
A16:
card J0 < k
by A11, CARD_1:50;
A17:
[:J,K:] = [:(J \ {j}),K:] \/ [:J0,K:]
by A15, ZFMISC_1:120;
A18:
J \ {j} misses J0
by XBOOLE_1:79;
A19:
Sum (f | J) = (Sum (f | (J \ {j}))) + (Sum (f | J0))
by Th26, A15, XBOOLE_1:79;
A20:
[:(J \ {j}),K:] misses [:J0,K:]
by A18, ZFMISC_1:127;
A21:
Sum ((multnat * [:f,g:]) | [:J0,K:]) = (Sum (f | J0)) * (Sum (g | K))
by A16, A2;
thus Sum ((multnat * [:f,g:]) | [:J,K:]) =
(Sum ((multnat * [:f,g:]) | [:(J \ {j}),K:])) + (Sum ((multnat * [:f,g:]) | [:J0,K:]))
by A20, Th26, A17
.=
((Sum (f | (J \ {j}))) * (Sum (g | K))) + ((Sum (f | J0)) * (Sum (g | K)))
by A21, A2, A14, A3, A13, A15
.=
(Sum (f | J)) * (Sum (g | K))
by A19
;
:: thesis: verum end; end;
end;
end;
A22:
for k being Nat holds S1[k]
from NAT_1:sch 4(A1);
S1[ card J]
by A22;
hence
Sum ((multnat * [:f,g:]) | [:J,K:]) = (Sum (f | J)) * (Sum (g | K))
; :: thesis: verum