defpred S1[ Element of NAT ] means for a, k being Element of NAT
for X being set
for F being FinSequence of SetPrimes
for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F & len F = $1 holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) );
A2:
S1[ 0 ]
A8:
for n being Element of NAT st S1[n] holds
S1[n + 1]
proof
let n be
Element of
NAT ;
:: thesis: ( S1[n] implies S1[n + 1] )
assume A9:
S1[
n]
;
:: thesis: S1[n + 1]
for
a,
k being
Element of
NAT for
X being
set for
F being
FinSequence of
SetPrimes for
p being
Prime st
X c= SetPrimes &
X c= Seg k &
F = Sgm X &
a = Product F &
len F = n + 1 holds
( (
p in rng F implies
p |-count a = 1 ) & ( not
p in rng F implies
p |-count a = 0 ) )
proof
let a,
k be
Element of
NAT ;
:: thesis: for X being set
for F being FinSequence of SetPrimes
for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F & len F = n + 1 holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )let X be
set ;
:: thesis: for F being FinSequence of SetPrimes
for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F & len F = n + 1 holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )let F be
FinSequence of
SetPrimes ;
:: thesis: for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F & len F = n + 1 holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )let p be
Prime;
:: thesis: ( X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F & len F = n + 1 implies ( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) ) )
assume A10:
(
X c= SetPrimes &
X c= Seg k &
F = Sgm X &
a = Product F )
;
:: thesis: ( not len F = n + 1 or ( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) ) )
assume A11:
len F = n + 1
;
:: thesis: ( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )
set x =
F . (n + 1);
A12:
Seg (n + 1) = dom F
by A11, FINSEQ_1:def 3;
then
n + 1
in dom F
by FINSEQ_1:5;
then A13:
F . (n + 1) in rng F
by FUNCT_1:def 5;
rng F c= SetPrimes
by FINSEQ_1:def 4;
then reconsider x =
F . (n + 1) as
Prime by A13, NEWTON:def 6;
set X1 =
X \ {x};
A14:
X \ {x} c= X
by XBOOLE_1:36;
then A15:
X \ {x} c= SetPrimes
by A10, XBOOLE_1:1;
A16:
X \ {x} c= Seg k
by A10, A14, XBOOLE_1:1;
set F1 =
Sgm (X \ {x});
reconsider F1 =
Sgm (X \ {x}) as
FinSequence of
NAT ;
set a1 =
Product F1;
set F2 =
Sgm {x};
A17:
rng F = X
by A10, FINSEQ_1:def 13;
then A18:
{x} c= Seg k
by TARSKI:def 3;
A19:
for
m1,
n1 being
Element of
NAT st
m1 in X \ {x} &
n1 in {x} holds
m1 < n1
proof
let m1,
n1 be
Element of
NAT ;
:: thesis: ( m1 in X \ {x} & n1 in {x} implies m1 < n1 )
assume A20:
(
m1 in X \ {x} &
n1 in {x} )
;
:: thesis: m1 < n1
then A21:
m1 in rng F
by A14, A17;
A22:
F is
one-to-one
by A10, FINSEQ_3:99;
then A23:
m1 in dom (F " )
by A21, FUNCT_1:55;
set l =
(F " ) . m1;
(F " ) . m1 in rng (F " )
by A23, FUNCT_1:def 5;
then A24:
(F " ) . m1 in Seg (n + 1)
by A12, A22, FUNCT_1:55;
then reconsider l =
(F " ) . m1 as
Element of
NAT ;
A25:
( 1
<= l &
l <= n + 1 )
by A24, FINSEQ_1:3;
set n' =
n + 1;
A26:
m1 = F . l
by A14, A17, A20, A22, FUNCT_1:57;
A27:
n1 = F . (n + 1)
by A20, TARSKI:def 1;
not
n + 1
= l
by A20, A26, ZFMISC_1:64;
then
l < n + 1
by A25, XXREAL_0:1;
hence
m1 < n1
by A10, A11, A25, A26, A27, FINSEQ_1:def 13;
:: thesis: verum
end;
A28:
(X \ {x}) \/ {x} =
X \/ {x}
by XBOOLE_1:39
.=
X
by A13, A17, ZFMISC_1:46
;
then A29:
F = F1 ^ (Sgm {x})
by A10, A16, A18, A19, FINSEQ_3:48;
then A30:
len F = (len F1) + (len (Sgm {x}))
by FINSEQ_1:35;
A31:
Sgm {x} = <*x*>
by FINSEQ_3:50;
then A32:
n + 1
= (len F1) + 1
by A11, A30, FINSEQ_1:56;
A33:
rng F c= SetPrimes
by FINSEQ_1:def 4;
rng F1 c= rng F
by A29, FINSEQ_1:42;
then A34:
rng F1 c= SetPrimes
by A33, XBOOLE_1:1;
then reconsider F1 =
F1 as
FinSequence of
SetPrimes by FINSEQ_1:def 4;
A35:
rng (Sgm {x}) = {x}
by A31, FINSEQ_1:56;
A36:
Product F =
Product (F1 ^ (Sgm {x}))
by A10, A16, A18, A19, A28, FINSEQ_3:48
.=
Product (F1 ^ <*x*>)
by FINSEQ_3:50
.=
(Product F1) * x
by RVSUM_1:126
;
then
Product F1 <> 0
by Th42;
then A37:
p |-count a = (p |-count (Product F1)) + (p |-count x)
by A10, A36, NAT_3:28;
A38:
rng F1 = X \ {x}
by A16, FINSEQ_1:def 13;
hence
( (
p in rng F implies
p |-count a = 1 ) & ( not
p in rng F implies
p |-count a = 0 ) )
by A39;
:: thesis: verum
end;
hence
S1[
n + 1]
;
:: thesis: verum
end;
A45:
for n being Element of NAT holds S1[n]
from NAT_1:sch 1(A2, A8);
let a, k be Element of NAT ; :: thesis: for X being set
for F being FinSequence of SetPrimes
for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )
let X be set ; :: thesis: for F being FinSequence of SetPrimes
for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )
let F be FinSequence of SetPrimes ; :: thesis: for p being Prime st X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F holds
( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) )
let p be Prime; :: thesis: ( X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F implies ( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) ) )
reconsider F = F as FinSequence of REAL by A1;
ex n being Element of NAT st n = len F
;
hence
( X c= SetPrimes & X c= Seg k & F = Sgm X & a = Product F implies ( ( p in rng F implies p |-count a = 1 ) & ( not p in rng F implies p |-count a = 0 ) ) )
by A45; :: thesis: verum