let H be LTL-formula; :: thesis: ( H is Release implies H . 1 = 5 )
assume H is Release ; :: thesis: H . 1 = 5
then consider F, G being LTL-formula such that
A1: H = F 'R' G by Def1901;
( H = (<*5*> ^ F) ^ G & (<*5*> ^ F) ^ G = <*5*> ^ (F ^ G) ) by A1, FINSEQ_1:45;
hence H . 1 = 5 by FINSEQ_1:58; :: thesis: verum