hereby :: thesis: ( ( for x being set holds -infty < f . x ) implies f is without-infty ) end;
assume A2: for x being set holds -infty < f . x ; :: thesis: f is without-infty
now
assume -infty in rng f ; :: thesis: contradiction
then consider x being set such that
A3: ( x in dom f & f . x = -infty ) by FUNCT_1:def 5;
thus contradiction by A2, A3; :: thesis: verum
end;
hence f is without-infty by Def3; :: thesis: verum