let X be non empty set ; :: thesis: for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let S be SigmaField of X; :: thesis: for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let M be sigma_Measure of S; :: thesis: for f being PartFunc of X,ExtREAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let f be PartFunc of X,ExtREAL ; :: thesis: for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let A, B be Element of S; :: thesis: ( ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B implies Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B)) )
assume that
A1:
ex E being Element of S st
( E = dom f & f is_measurable_on E )
and
A2:
( f is nonnegative & A misses B )
; :: thesis: Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
consider E being Element of S such that
A3:
( E = dom f & f is_measurable_on E )
by A1;
A4:
ex C being Element of S st
( C = dom (f | (A \/ B)) & f | (A \/ B) is_measurable_on C )
A9:
integral+ M,(f | (A \/ B)) = (integral+ M,(f | A)) + (integral+ M,(f | B))
by A1, A2, Th87;
A10:
Integral M,(f | (A \/ B)) = integral+ M,(f | (A \/ B))
by A2, A4, Th21, Th94;
ex C being Element of S st
( C = dom (f | A) & f | A is_measurable_on C )
proof
take C =
E /\ A;
:: thesis: ( C = dom (f | A) & f | A is_measurable_on C )
thus
dom (f | A) = C
by A3, RELAT_1:90;
:: thesis: f | A is_measurable_on C
A11:
f is_measurable_on C
by A3, MESFUNC1:34, XBOOLE_1:17;
A12:
C = (dom f) /\ C
by A3, XBOOLE_1:17, XBOOLE_1:28;
A13:
dom (f | A) =
C
by A3, RELAT_1:90
.=
dom (f | C)
by A12, RELAT_1:90
;
for
x being
set st
x in dom (f | A) holds
(f | A) . x = (f | C) . x
then
f | C = f | A
by A13, FUNCT_1:9;
hence
f | A is_measurable_on C
by A11, A12, Th48;
:: thesis: verum
end;
then A15:
Integral M,(f | A) = integral+ M,(f | A)
by A2, Th21, Th94;
ex C being Element of S st
( C = dom (f | B) & f | B is_measurable_on C )
proof
take C =
E /\ B;
:: thesis: ( C = dom (f | B) & f | B is_measurable_on C )
thus
dom (f | B) = C
by A3, RELAT_1:90;
:: thesis: f | B is_measurable_on C
A16:
f is_measurable_on C
by A3, MESFUNC1:34, XBOOLE_1:17;
A17:
C = (dom f) /\ C
by A3, XBOOLE_1:17, XBOOLE_1:28;
A18:
dom (f | B) =
C
by A3, RELAT_1:90
.=
dom (f | C)
by A17, RELAT_1:90
;
for
x being
set st
x in dom (f | B) holds
(f | B) . x = (f | C) . x
then
f | C = f | B
by A18, FUNCT_1:9;
hence
f | B is_measurable_on C
by A16, A17, Th48;
:: thesis: verum
end;
hence
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
by A2, A9, A10, A15, Th21, Th94; :: thesis: verum